Question

我有一张包含以下数据的表格：

col-1   col-2   col-3   col-4   col-5   col-6   col-7
-----   -----   -----   -----   -----   -----   -----
10      2       30      13      A       0.1     0.3
10      2       30      13      B       0.2     0.9
10      2       30      13      C       0.8     0.7
10      2       30      13      D       0.4     0.5
2       1       8       11      A       0.3     0.4
2       1       8       11      B       0.9     0.2
2       1       8       11      C       0.1     0.8
2       1       8       11      D       0.2     0.5

我必须提出下表:(此处col-1至col-4具有4个不同col-5值的相同值）

col-1    col-2    col-3    col-4    A_6    B_6    C_6    D_6    A_7    B_7  
-----    -----    -----    -----    ---    ---    ---    ---    ---    ---  
10        2         30      13      0.1    0.2    0.8    0.4    0.3    0.9  
2         1         8       11      0.3    0.9    0.1    0.2    0.4    0.2

知道如何实现这个目标吗？

考虑 A_6，因为A_COL_6表示A的Col_6值

Answer 1

WITH
    temp_t
    AS
        (SELECT '10'     col_1,
                '2'      col_2,
                '30'     col_3,
                '13'     col_4,
                'A'      col_5,
                0.1      col_6,
                0.3      col_7
           FROM DUAL
         UNION ALL
         SELECT '10', '2', '30', '13', 'B', 0.2, 0.9 FROM DUAL
         UNION ALL
         SELECT '10', '2', '30', '13', 'C', 0.8, 0.7 FROM DUAL
         UNION ALL
         SELECT '10', '2', '30', '13', 'D', 0.4, 0.5 FROM DUAL
         UNION ALL
         SELECT '2', '1', '8', '11', 'A', 0.3, 0.4 FROM DUAL
         UNION ALL
         SELECT '2', '1', '8', '11', 'B', 0.9, 0.2 FROM DUAL
         UNION ALL
         SELECT '2', '1', '8', '11', 'C', 0.1, 0.8 FROM DUAL
         UNION ALL
         SELECT '2', '1', '8', '11', 'D', 0.2, 0.5 FROM DUAL)
SELECT *
  FROM temp_t
       PIVOT (SUM (col_6) AS c6, SUM (col_7) AS c7
             FOR (col_5)
             IN ('A', 'B', 'C', 'D'))

Answer 2

您可以将CASE WHEN表达式与聚合函数

一起使用

WITH T AS(
     SELECT '10'  col_1,'2'   col_2,'30'  col_3,'13' col_4,'A'  col_5, '0.1'  col_6,'0.3' col_7 FROM DUAL
     UNION ALL
     SELECT '10', '2', '30', '13', 'B', '0.2','0.9' FROM DUAL
     UNION ALL
     SELECT '10', '2', '30', '13', 'C', '0.8','0.7' FROM DUAL
     UNION ALL
     SELECT '10', '2', '30', '13', 'D', '0.4','.5' FROM DUAL
     UNION ALL
     SELECT '2' ,'1' ,'8' ,'11','A' , '0.3','0.4'   FROM DUAL
     UNION ALL
     SELECT '2', '1', '8', '11', 'B', '0.9','0.2'   FROM DUAL
     UNION ALL
     SELECT '2', '1', '8', '11', 'C', '0.1','0.8'   FROM DUAL
     UNION ALL
     SELECT '2', '1', '8', '11', 'D', '0.2','0.5'   FROM DUAL
 )
 SELECT COL_1,
        COL_2,
        COL_3,
        COL_4,
        MAX(CASE WHEN COL_5 = 'A' THEN COL_6 ELSE '0' END) A_6,
        MAX(CASE WHEN COL_5 = 'B' THEN COL_6 ELSE '0' END) B_6,
        MAX(CASE WHEN COL_5 = 'C' THEN COL_6 ELSE '0' END) C_6,
        MAX(CASE WHEN COL_5 = 'D' THEN COL_6 ELSE '0' END) D_6,
        MAX(CASE WHEN COL_5 = 'A' THEN COL_7 ELSE '0' END) A_7,
        MAX(CASE WHEN COL_5 = 'B' THEN COL_7 ELSE '0' END) B_7
 FROM T
 GROUP BY 
        COL_1,
        COL_2,
        COL_3,
        COL_4

SQLFIDDLE：http://sqlfiddle.com/#!4/b9bb1/21

SQL查询：sql中的列的汇编：Oracle

2 个答案: