Question

我正在尝试创建一个删除具有特定设备ID和产品ID的条目的函数。该函数删除该行但运行带有错误的else语句。 mysqli_affected_rows（）期望参数1为mysql

该功能还必须重定向到dashboard.php，但不是。任何帮助将不胜感激。

if(isset($_POST['remove_product'])){

    //recieve input
    $DeviceID = mysqli_real_escape_string($db,$_POST['DeviceID']);
    $productID = mysqli_real_escape_string($db,$_POST['productID']);

    $name = $_SESSION['username'];


    $sql="DELETE FROM products WHERE deviceid = '$DeviceID' AND productid = '$productID' AND username = '$name'";
    $resultsql = mysqli_query($db,$sql);


    if($resultsql != FALSE && mysqli_affected_rows($resultsql) == 1){

            echo "Device/Product is deleted!";
            header('Location: dashboard.php');
            exit;
          }

    else{
        echo "Device/Product not registered";

    }

}

Answer 1

更好的想法是使用prepared statement，bind the $DeviceID, $productID and $name parameters然后检查$stmt->affected_rows

// Exceptions are much easier to deal with
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);

$stmt = $db->prepare('DELETE FROM products WHERE deviceid = ? AND productid = ? AND username = ?');
$stmt->bind_param('iis', $_POST['DeviceID'], $_POST['productID'], $_SESSION['username']);
$stmt->execute();
if ($stmt->affected_rows === 1) {
    // and so on.

Answer 2

mysqli_affected_rows（）应该引用连接而不是查询。 reference

此外，您无法在 echo 语句php docs

之后使用标题

查看更新的代码（未测试）

if(isset($_POST['remove_product'])){

    //recieve input
    $DeviceID = mysqli_real_escape_string($db,$_POST['DeviceID']);
    $productID = mysqli_real_escape_string($db,$_POST['productID']);

    $name = $_SESSION['username'];


    $sql="DELETE FROM products WHERE deviceid = '$DeviceID' AND productid = '$productID' AND username = '$name'";
    $resultsql = mysqli_query($db,$sql);


    if($resultsql && mysqli_affected_rows($db) == 1){
            header('Location: dashboard.php');
            exit;
          }

    else{
        echo "Device/Product not registered";

    }

}

Answer 3

尝试替换

mysqli_affected_rows($resultsql) to mysqli_affected_rows($db)

PHP删除功能不会重定向到标头位置，但会删除条目

3 个答案: