为课程编写示例程序。继续收到此错误:
ValueError: invalid literal for int() with base 10: ''
第1行。
这是包含错误的块。程序运行完全正常,但学校的测试软件失败了。我做错了什么?
"""
HouseSign.py - This program calculates prices for custom house signs.
"""
# Declare and initialize variables here.
# Charge for this sign.
# Number of characters.
# Color of characters.
# Type of wood.
charge = 0
numChars = int(input("How many letters do you want? "))
color = input("What color letters do you want? ")
woodType = input("What type of wood do you want? ")
if numChars < 5:
charge = charge + 0
else:
charge = charge + 0
if numChars >= 6:
charge = (numChars - 5 ) * 4
else:
charge = charge + 0
if color=="gold":
charge = charge + 15
else:
charge = charge + 0
if woodType=="oak":
charge = charge + 20
else:
charge = charge + 0
charge = charge + 35
# Write assignment and if statements here as appropriate.
# Output Charge for this sign.
print("The charge for this sign is $" + str(charge) + ".")
答案 0 :(得分:0)
正如评论中所提到的,你可能完全没有任何价值地进入:
试试这个:
while True:
try:
numChars = int(input("How many letters do you want? "))
break
except:
print("Oops, make sure you're entering a valid value")
while True:
try:
color = input("What color letters do you want? ")
break
except:
print("Oops, make sure you're entering a valid value")
while True:
try:
woodType = input("What type of wood do you want? ")
break
except:
print("Oops, make sure you're entering a valid value")
这样做很简单: 它“尝试”运行代码,但如果它出现错误,他将再次请求输入,并打印由于while循环而在except中的任何内容。 每当它做正确的事情时它就会中断。 祝你好运!
修改强>:
BTW,请考虑使用charge += 2
,而不是charge = charge + 2
。它只是一个捷径,但使代码更清晰。