SQL区别于多个Criteria

Question

我想根据SampleData Table & Output生成表格输出。我的SQL查询如下，但它没有给我最后三列的正确结果

SELECT
  UserLogin,
  COUNT(DISTINCT consumerID) AS TotalUniqueconsumerIDs,  
  COUNT(DISTINCT (CASE
        WHEN ActivitiesCompleted > 0 AND QuizCompleted <= 0 THEN consumerID END)) AS YesActivityNoQuiz,
  COUNT(DISTINCT (CASE
        WHEN ActivitiesCompleted <= 0 AND QuizCompleted > 0 THEN consumerID END)) AS NoActivityYesQuiz,  
COUNT(DISTINCT (CASE
        WHEN ActivitiesCompleted >= 1 AND QuizCompleted >= 1 THEN consumerID END)) AS YesActivityYesQuiz
FROM
  TableName
GROUP BY
  UserLogin

非常感谢任何帮助。

更多信息：

也许我上面并不清楚所以提供更多信息：

我创建了另一个样本表，其中只有1个UserLogin的数据，看起来像this，如果我在Excel外部转移此示例数据集，我会看到this

正如您所看到的，此透视屏幕截图中此表中的consumerID都有超过1个ActivitiesCompleted以及1个QuizCompleted。

基于我上面的查询的SQL输出看起来像this

然而，基于Pivot截图，我期望YesActivityYesQuiz列中的1和YesActivityNoQuiz＆amp;中的0。 NoActivityYesQuiz

示例数据：

Date,UserLogin,consumerID,ActivitiesCompleted,QuizCompleted
6/8/2018,aasufhar,consumerA,0,1
6/8/2018,aasufhar,consumerA,0,0
6/8/2018,aasufhar,consumerA,1,0
6/8/2018,aasufhar,consumerA,1,0
6/8/2018,aasufhar,consumerA,1,0
6/8/2018,aasufhar,consumerA,1,0
6/8/2018,aasufhar,consumerA,1,0
6/8/2018,aasufhar,consumerA,1,0
6/8/2018,aasufhar,consumerA,1,0
6/8/2018,aasufhar,consumerA,2,0
6/8/2018,aasufhar,consumerA,1,0
6/8/2018,aasufhar,consumerA,1,0
6/8/2018,aasufhar,consumerA,1,0
6/8/2018,aasufhar,consumerA,0,0
6/8/2018,aasufhar,consumerA,0,0
6/8/2018,aasufhar,consumerA,0,0
6/8/2018,aasufhar,consumerA,0,0
6/8/2018,aasufhar,consumerA,0,0
6/8/2018,aasufhar,consumerA,0,0
6/8/2018,aasufhar,consumerA,0,0
6/8/2018,aasufhar,consumerA,0,0
6/8/2018,aasufhar,consumerA,0,0
6/8/2018,aasufhar,consumerA,0,0
6/8/2018,aasufhar,consumerA,0,0
6/8/2018,aasufhar,consumerB,0,1
6/8/2018,aasufhar,consumerB,0,0
6/8/2018,aasufhar,consumerB,2,0
6/8/2018,aasufhar,consumerB,1,0
6/8/2018,aasufhar,consumerB,1,0
6/8/2018,aasufhar,consumerB,1,0
6/8/2018,aasufhar,consumerB,0,0
6/8/2018,aasufhar,consumerB,0,0
6/8/2018,aasufhar,consumerB,0,0
6/8/2018,aasufhar,consumerB,0,0
6/8/2018,aasufhar,consumerB,0,0

Answer 1

有问题的查询似乎对我来说是正确的（至少它会返回预期结果中显示的内容）

不过，我可以提出更简洁的版本（BigQuery Standard SQL）

#standardSQL
SELECT UserLogin, 
  COUNT(DISTINCT consumerID) AS TotalUniqueconsumerIDs,  
  COUNT(DISTINCT IF(ActivitiesCompleted > 0 AND QuizCompleted <= 0, consumerID, NULL)) AS YesActivityNoQuiz,
  COUNT(DISTINCT IF(ActivitiesCompleted <= 0 AND QuizCompleted > 0, consumerID, NULL)) AS NoActivityYesQuiz,  
  COUNT(DISTINCT IF(ActivitiesCompleted >= 1 AND QuizCompleted >= 1, consumerID, NULL)) AS YesActivityYesQuiz
FROM TableName
GROUP BY UserLogin

  

根据OP

的最新示例/解释更新了查询

#standardSQL
SELECT UserLogin, 
  COUNT(DISTINCT consumerID) AS TotalUniqueconsumerIDs,  
  COUNT(DISTINCT IF(ActivitiesCompleted > 0 AND QuizCompleted <= 0, consumerID, NULL)) AS YesActivityNoQuiz,
  COUNT(DISTINCT IF(ActivitiesCompleted <= 0 AND QuizCompleted > 0, consumerID, NULL)) AS NoActivityYesQuiz,  
  COUNT(DISTINCT IF(ActivitiesCompleted >= 1 AND QuizCompleted >= 1, consumerID, NULL)) AS YesActivityYesQuiz,
  COUNT(DISTINCT IF(ActivitiesCompleted <= 0 AND QuizCompleted <= 0, consumerID, NULL)) AS NoActivityNoQuiz
FROM (
  SELECT UserLogin,consumerID,
    SUM(ActivitiesCompleted) ActivitiesCompleted,
    SUM(QuizCompleted) QuizCompleted
  FROM TableName
  GROUP BY UserLogin,consumerID
)
GROUP BY UserLogin

Answer 2

也许你只想要max()：

SELECT UserLogin, COUNT(DISTINCT consumerID) AS TotalUniqueconsumerIDs,  
       MAX(CASE WHEN ActivitiesCompleted > 0 AND QuizCompleted <= 0 THEN 1 ELSE 0 END) AS YesActivityNoQuiz,
       MAX(CASE WHEN ActivitiesCompleted <= 0 AND QuizCompleted > 0 THEN 1 ELSE 0 END) AS NoActivityYesQuiz,  
       MAX(CASE WHEN ActivitiesCompleted >= 1 AND QuizCompleted >= 1 THEN 1 ELSE 0 END) AS YesActivityYesQuiz
FROM TableName
GROUP BY UserLogin;

Answer 3

您必须在group by子句中包含ActivitiesCompleted，因为您在case语句中使用了它。它没有抛出你的错误？

SELECT
  UserLogin,
  COUNT(DISTINCT consumerID) AS TotalUniqueconsumerIDs,  
  COUNT(DISTINCT (CASE
        WHEN ActivitiesCompleted > 0 AND QuizCompleted <= 0 THEN consumerID END)) AS YesActivityNoQuiz,
  COUNT(DISTINCT (CASE
        WHEN ActivitiesCompleted <= 0 AND QuizCompleted > 0 THEN consumerID END)) AS NoActivityYesQuiz,  
COUNT(DISTINCT (CASE
        WHEN ActivitiesCompleted >= 1 AND QuizCompleted >= 1 THEN consumerID END)) AS YesActivityYesQuiz
FROM
  TableName
GROUP BY
  UserLogin,ActivitiesCompleted