Question

我需要显示：

/images/image1.jmp如果数字是正数

或

/images/image2.jpg如果数字为负数

或

如果数字为0，则
/ images / image3。

$stmt = sqlsrv_query($conn,$sql);
    echo "<table border='1'><tr><th>Offense</th><th>Previous Date Range</th><th>Current Date Range</th><th>Difference</th><th>Percentage Difference</><th>Up or down image in this column</></tr>";

while( $row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC) ) 
{
    echo "<tr>";
    echo "<td>" . $row['Offense']. "</td>";
    echo "<td>" . $row['PreviousDateRange']."</td>";
    echo "<td>" . $row['DateRange']."</td>";
    echo "<td>" . $row['difference1']."</td>";
    echo "<td>" . $row['percentchange']."</td>";
    echo "<td>" . $row['']. "</td>";
    }
    echo "</table>";         

 ?>

我找到了这段代码，如果将其合并到echo "<td>" . $row['']. "</td>但没有任何运气，我尝试了不同的方法。

我得到了代码但无法操纵它以适应它需要做的事情。我确定这是一个简单的解决方案。沮丧。

switch ($myNumber) {
  case 0:
    echo "Zero is not a valid value.";
    break;
  case $myNumber < 0:
    echo "Negative numbers are not allowed.";
    break;
  default:
    echo "Great! Ready to make calculations.";
    break;
}

感谢帮助人员。得到了有效的答案。

Answer 1

您没有告诉我们$myNumber来自哪里，所以如果变量名称不同，只需在下面的代码中修改它。

echo '<td>/images/image' . ($myNumber == 0 ? '3' : ($myNumber >= 1 ? '1' : '2')) . '.jpg</td>';

Answer 2

我认为这是一个更具可读性的解决方案我使用数组来保存链接并使用计算来查看它是否为负数。

$img = ["-1" => "/images/image2.jpg", 
"0" => "/images/image3.jpg",
"1" => "/images/image1.jpg"];

$number = 0;

Echo ($number == 0 ? $img[$number] : $img[$number/abs($number)]);

https://3v4l.org/JstZl

如果数字为正数，则计算结果为15/15 => 1 如果数字为负数-10/10 => -1。

编辑：

$stmt = sqlsrv_query($conn,$sql);
echo "<table border='1'><tr><th>Offense</th><th>Previous Date Range</th><th>Current Date Range</th><th>Difference</th><th>Percentage Difference</><th>Up or down image in this column</></tr>";
$img = ["-1" => "/images/image2.jpg", 
"0" => "/images/image3.jpg",
"1" => "/images/image1.jpg"];


while( $row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC) ) 
{
    echo "<tr>";
    echo "<td>" . $row['Offense']. "</td>";
    echo "<td>" . $row['PreviousDateRange']."</td>";
    echo "<td>" . $row['DateRange']."</td>";
    echo "<td>" . $row['difference1']."</td>";
    echo "<td>" . $row['percentchange']."</td>";
    Echo '<td><img src="' . ($row['percentchange'] == 0 ? $img[$row['percentchange']] : $img[$row['percentchange']/abs($row['percentchange'])]) . '"></td>';
}
echo "</table>";

Answer 3

尝试：

if($myNumber < 0) {
    //show /images/image2.jpg
}
if($myNumber == 0) {
    //show /images/image3
}
if($myNumber > 0) {
    //show /images/image1.jmp
}

在您的代码中：

while( $row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC) ) 
{
  echo "<tr>";
  echo "<td>" . $row['Offense']. "</td>";
  echo "<td>" . $row['PreviousDateRange']."</td>";
  echo "<td>" . $row['DateRange']."</td>";
  echo "<td>" . $row['difference1']."</td>";
  echo "<td>" . $row['percentchange']."</td>";

  echo "<td>";
    if($row['percentchange'] < 0) {
      //show /images/image2.jpg
    }
    if($row['percentchange'] == 0) {
      //show /images/image3
    }
    if($row['percentchange'] > 0) {
      //show /images/image1.jmp
    }
  echo "</td>";

}

根据您的其他评论，我们假设$row['percentchange']是您特别关注的数字。

PHP根据正数或负数显示图像

3 个答案: