Question

我有一个包含文件的文件夹：File1.txt和File2.txt

file1.txt的内容是：

"DTS053C0 RUN DATE 10/01/11 DATATRAK SYSTEM PAGE 001
RUN TIME 13:35:08
INPUT PROGRAM TRANSMISSION STATUS REPORT
STATUS - INPUT RECEIVED BY DTCC'S DATATRAK SYSTEM
DETAIL RECORDS RECEIVED 0
HEADER RECORD RECEIVED
HDR.SSYSID.E00.CORIG.SSUBOMMDDYYYY HEADERFILEDESCRIPTION N001 *
REJECTED
NO MATCH ON EXPECTED MASTER FOR HEADER"

file2.txt的内容是：

"The confirm file received from DTCC will be in the following format:
DTS053C0 RUN DATE 10/01/11 DATATRAK SYSTEM PAGE 001
RUN TIME 12:53:32
INPUT PROGRAM TRANSMISSION STATUS REPORT
STATUS - INPUT RECEIVED BY DTCC'S DATATRAK SYSTEM
DETAIL RECORDS RECEIVED 22
HEADER RECORD RECEIVED
HDR.SSYSID.E00.CORIG.SSUBOMMDDYYYY HEADERFILEDESCRIPTION N001 *
ACCEPTED
Example"

我正在寻找一个批处理脚本来分别扫描这两个文件的内容，并识别包含单词“REJECTED”的文件，然后发送一封电子邮件到我的email-id，就像通知说“这个文件已经被拒绝，请检查“。

我使用blat发送电子邮件作为通知*

Answer 1

将@Stephans建议包装成批处理：

Findstr /M仅报告与REJECTED，
for /f处理此输出，集合收集此内容变量找到了。第一个条目产生一个主要逗号。
最后将此变量内容作为参数传递给子例程：Blat第一个逗号被第2个子串%Found:~1%删除 pos（零基础）
在子目录中，您可以使用%* =（所有传递的参数）将其作为blat例程的邮件主题或正文。

:: Q:\Test\2018\06\14\SO_50858355.cmd
@Echo off & Setlocal EnableDelayedExpansion
Set "Search=REJECTED"
Set "Files=file?.txt"
Set "Found="
for /f "delims=" %%A in ('
  findstr /m /i "%Search%" %Files%
') Do set "Found=!Found!,%%A"
If Defined Found (
    Call :Blat %Found:~1%
) Else (
    Echo No files "%Files%" containing "%Search%" found
)
Pause
Goto :Eof

:Blat
Echo found Rejected in %1
If "%2" neq "" (shift & goto :Blat)

示例输出：

> SO_50858355.cmd
Yourblatcommand found Rejected in file1.txt

新的样本输出：

> SO_50858355.cmd
found Rejected in file3.txt
found Rejected in file1.txt

批处理文件只搜索当前文件夹和通配符file?.txt，因此您必须调整变量以满足您的需要或首先设置其他工作目录。

使用循环使用批处理脚本

1 个答案: