解析错误：语法错误，意外＆＃39; $结果＆＃39; （T_VARIABLE）在第6行的C：\ xampp \ htdocs \ login.php中

Question

我的PHP代码是

<?php
require "conn.php";
$user_name = "";
$user_pass = "";
$mysql_qry = "select * from logindetails where User_id like '$user_name' and 
Password '$user_pass';"
$result = mysqli_query($conn ,$mysql_qry);
if(mysqli_num_rows($result) > 0){
echo "login success";
}
else{
echo "login not success";
}
?>

错误是解析错误：语法错误，意外＆＃39; $结果＆＃39;第6行的C：\ xampp \ htdocs \ login.php中的（T_VARIABLE）

Answer 1

您错误地放了分号，在查询结尾处添加分号并使用＆＃39; =＆＃39;密码后

$mysql_qry = "select * from logindetails where User_id like '$user_name' and 
Password = '$user_pass'";

Answer 2

没什么..你刚才放错了分号。

只需更改此

$mysql_qry = "select * from logindetails where User_id like '$user_name' and 
Password '$user_pass';"

到此。

$mysql_qry = "select * from logindetails where User_id like '$user_name' and 
Password '$user_pass'";