使用Flask部署Azure Web时,我一直收到以下错误:
Unhandled exception in wfastcgi.py: Traceback (most recent call last):
File "D:\home\python364x64\wfastcgi.py", line 791, in main
env, handler = read_wsgi_handler(response.physical_path)
File "D:\home\python364x64\wfastcgi.py", line 633, in read_wsgi_handler
handler = get_wsgi_handler(os.getenv("WSGI_HANDLER"))
File "D:\home\python364x64\wfastcgi.py", line 603, in get_wsgi_handler
handler = getattr(handler, name)
AttributeError: module 'app' has no attribute 'app'
这是我的应用程序的结构:
|-app
|- __init__.py
|- mod1
|- mod2
|-config.py
|-runserver.py
|-web.config
这是我的web.config文件:
<?xml version="1.0" encoding="utf-8"?>
<configuration>
<appSettings>
<add key="WSGI_HANDLER" value="app.app"/>
<add key="PYTHONPATH" value="D:\home\site\wwwroot"/>
<add key="WSGI_LOG" value="D:\home\LogFiles\wfastcgi.log"/>
</appSettings>
<system.webServer>
<handlers>
<add name="PythonHandler" path="*" verb="*" modules="FastCgiModule" scriptProcessor="D:\home\python364x64\python.exe|D:\home\python364x64\wfastcgi.py" resourceType="Unspecified" requireAccess="Script"/>
</handlers>
</system.webServer>
</configuration>
config.py:
import os
app_dir = os.path.abspath(os.path.dirname(__file__))
class BaseConfig:
SECRET_KEY = os.environ.get('SECRET_KEY') or 'A SECRET KEY'
class DevelopementConfig(BaseConfig):
DEBUG = True
runserver.py:
import os
from app import db, create_app
app = create_app(os.getenv('FLASK_ENV') or 'config.DevelopementConfig')
if __name__ == '__main__':
app.run()
和app。 init .py:
from flask import Flask
def create_app(config):
app = Flask(__name__)
app.config.from_object(config)
return app
我尝试将wsgi.py包含在:
from app import app as application
与runserver.py处于同一级别,但仍然出现上述错误。我在这里缺少什么?
答案 0 :(得分:2)
那么,WSGI如何运作?它启动,导入您的应用程序并调用它的方法来处理请求。 WSGI的<add key="WSGI_HANDLER" value="app.app"/>
表示导入模块应用并从中获取变量应用。但在导入app.__init__.py之后,只有Flask
和create_app
变量,具有Flask-class和create_app-function。所以你应该在WSGI_HANDLER中设置指向flask应用程序的值,runserver.app
或app.create_app()
(我不知道究竟是什么,使用正确的语法,Azure将app作为一个函数处理,但它{{3} })。