我试图在webView上加载一些网址,具体取决于listView上选择的项目,这是我的代码:
val animals = arrayOf("cat","dog", "mouse", "parrot", "lion", "panda")
internal lateinit var adapter: ArrayAdapter<String>
val list = findViewById(R.id.lista) as ListView
adapter = ArrayAdapter(
this@MainActivity,
android.R.layout.simple_list_item_1,
animals)
list.adapter = adapter
这是有条件的我试图上班
list.setOnItemClickListener { adapterView, view, i, l ->
if(list.selectedItemPosition.equals(1)){
webView.loadUrl("http://cat.com")
}
else if (lista.selectedItemPosition.equals(2)) {
webView.loadUrl("http://dog.com")
}
}
else if (lista.selectedItemPosition.equals(2)) {
webView.loadUrl("http://mouse.com")
}
}
else if (lista.selectedItemPosition.equals(2)) {
webView.loadUrl("http://parrot.com")
}
}
else if (lista.selectedItemPosition.equals(2)) {
webView.loadUrl("http://lion.com")
}
}
else if (lista.selectedItemPosition.equals(2)) {
webView.loadUrl("http://panda.com")
}
else{
toast("nothing")}
这是我想要的按钮,使包含te webView的布局可见:
testweb.setOnClickListener {
ListView.visibility= View.GONE
website.visibility= View.VISIBLE
}
这就是我设置ListView的方式:
<ListView
android:id="@+id/lista"
android:layout_width="match_parent"
android:layout_height="240dp"
android:focusable="true"
android:focusableInTouchMode="true"
android:choiceMode="singleChoice"
android:listSelector="@android:color/holo_orange_light" >
</ListView>
到目前为止,所有我都是吐司的信息&#34;没有&#34;的xD
提前感谢您的支持
答案 0 :(得分:1)
list.setOnItemClickListener { adapterView, view, i, l ->
when(i){
0 -> webView.loadUrl("some url")
1 -> webView.loadUrl("some url")
.....
}
}
INSIDE WEBVIEW
webview.apply{
settings.javaScriptEnabled = true
settings.loadWithOverviewMode = true
settings.useWideViewPort = true
webViewClient = MyClient()
loadUrl("http://www.naver.com")
}
inner class MyClient : WebViewClient() {
override fun shouldOverrideUrlLoading(view: WebView?, request:
WebResourceRequest?): Boolean {
view?.loadUrl(request?.url?.toString())
return true
}
}