2D列表仅按第一个数字排序

时间:2018-06-14 00:31:23

标签: python python-3.x list sorting

此二维列表包含姓名和分数。我需要它从第二列的降序值中排序。

scores = "scores.txt"
highScores = list()   # place all your processed lines in here

with open(scores) as fin:
    for line in fin:
       lineParts = line.split(": ")
       if len(lineParts) > 1:
           lineParts[-1] = lineParts[-1].replace("\n", "")
           highScores.append(lineParts)   # sorting uses lists
    highScores.sort(key = lambda x: x[1], reverse = True)
print(highScores)

with open('sorted.txt', 'w') as f:
    for item in highScores:
        f.write(str(item) +"\n")

输入是:

test1: 5
test2: 6
test3: 1
test4: 2
gd: 0
hfh: 5
hr: 3
test: 0
rhyddh: 0
Marty: 5425
testet: 425
place: 84
to: 41

但输出是:

['place', '84']
['test2', '6']
['Marty', '5425']
['test1', '5']
['hfh', '5']
['testet', '425']
['to', '41']
['hr', '3']
['test4', '2']
['test3', '1']
['gd', '0']
['test', '0']
['rhyddh', '0']

如图所示,它仅按第一个数字对列进行排序。我该如何解决这个问题?

1 个答案:

答案 0 :(得分:1)

您需要在排序键中将字符串转换为整数:

highScores.sort(key=lambda x: int(x[1]), reverse=True)

否则,正如您所发现的那样,您的排序将一次处理一个字符,正如您对字符串所期望的那样。