Question

我正在创建一个应用程序，并希望根据用户输入的数字用一个按钮更改屏幕。例如，如果用户输入＆＃34; 1234＆＃34;，程序将检查另一个类以查看该数字是否存在。如果是，则继续使用SceneOne。如果用户输入的数字与其他类中的数字相反，则转到SceneTwo。但是，当我尝试将位置设置为不同的场景时，它会忽略它并自动将我发送到第一个屏幕。

Storage.Java（包含预定义的数字）

int pin = 1234;
public int getPin() {
    return number;
}

我的另一个类:(按下指定按钮时执行的功能）

public void switchScenes(ActionEvent e) throws IOException {
    FXMLLoader loader = new FXMLLoader();
    loader.setLocation(getClass().getResource("/application/ScreenOne.fxml"));
    Parent changeScenes = loader.load();
    Scene firstScene = new Scene(changeScenes);
    Stage window = (Stage)((Node)e.getSource()).getScene().getWindow();

    Storage a = new Storage();
    int pin = a.getPin(); 

    if(Integer.parseInt((screen.getText())) == pin) {   
    //screen is a field where user can enter a number
        window.setScene(firstScene);
        window.show();
    }

    else if(Integer.parseInt(screen.getText()) == reverseNumber(pin)) {
        //if number entered is in reverse, change to ScreenTwo
    loader.setLocation(getClass().getResource("/application/ScreenTwo.fxml"));
    }

Answer 1

我可以在单个舞台上提供改变场景的格式：在第六行是所需的.fxml对象。您可以简单地创建一个if-then语句，并根据输入加载您想要的任何.fxml对象。当我想要改变项目中的场景时，这是我所依赖的代码片段。 {

@FXML
public void buttonclicked(ActionEvent event) throws IOException //This method loads a new scene in a current window
{
    //note that on this line you can substitue "Screen2.fxml" for a string chosen prior to this line.
    Parent loader = FXMLLoader.load(getClass().getResource("Screen2.fxml"));//Creates a Parent called loader and assign it as ScReen2.FXML

    Scene scene = new Scene(loader); //This creates a new scene called scene and assigns it as the Sample.FXML document which was named "loader"

    Stage app_stage = (Stage) ((Node) event.getSource()).getScene().getWindow(); //this accesses the window.

    app_stage.setScene(scene); //This sets the scene as scene

    app_stage.show(); // this shows the scene
}

}

JavaFX用一个按钮切换到不同的场景

1 个答案: