Question

如何使用sql2查询执行以下操作：

要求：

路径：/content/consumer

转到一个节点级别，例如：/ content / consumer / en-us
搜索在＆＃34; / content / consumer / en-us＆＃34;等路径字段中创作的字符串。
if (current Node != Pathfield)然后显示它。

重复步骤1到3所有其他语言环境（en-ca，fr-fr，de-de等）。

以下是我的尝试：

    SELECT parent.* FROM [nt:unstructured] AS parent INNER JOIN [nt:unstructured] AS child ON ISDESCENDANTNODE(child,parent) WHERE ISDESCENDANTNODE(parent, [/content/consumer/en-us/]) AND child.[*] = '/content/consumer/%'

The query read or traversed more than 100000 nodes. To avoid affecting other tasks, processing was stopped.

如果我跑：

SELECT * FROM [nt:unstructured] AS s WHERE ISDESCENDANTNODE('/content/consumer/en-us/ip') and s.* LIKE '/content/consumer/%'

这将显示所有路径，而不考虑本地路径。我在寻找的是： / content / consumer / [^ en-us]％（即不喜欢en-us）。

这是我到目前为止所做的：

Resource resource = request.getResourceResolver().getResource(path);
    Node node = resource.adaptTo(Node.class);

    ResourceResolver resourceResolver = request.getResourceResolver();

    try {
        NodeIterator list = node.getNodes();

        while (list.hasNext()) {
            Node currentSubNode = list.nextNode();
            subNodeName = currentSubNode.getPath();
            culture = extractCultureNodeName(subNodeName);
            fullTextPath = path + culture;

            Map<String, String> map = new HashMap<String, String>();
            map.put("type", "nt:base");
            map.put("path", subNodeName);
            map.put("fulltext", fullTextPath);

            if (StringUtils.isNotBlank(culture)) {
                Query query = queryBuilder.createQuery(PredicateGroup.create(map),
                        resourceResolver.adaptTo(Session.class));
                SearchResult result = query.getResult();

                for (Hit hit : result.getHits()) {
                         String output = hit.getPath();
                        LOG.info("HITs: " + hit.getPath());
                }
            }

        }

问题出在查询构建器中，我得到的命中数远远少于crxde中的裸xpath查询：

/jcr:root/content/consumer/en-us//element(*, nt:base)
[
(jcr:contains(., ‘/content/consumer/en-us’))
]

用于在路径

0 个答案: