SQL错误:mysqli_stmt :: bind_param():类型定义字符串中的元素数量与匹配变量的数量不匹配

时间:2018-06-13 16:36:50

标签: php mysql sql mysqli prepared-statement

我有以下代码:

$conn = new mysqli($DB, $username, $password, $dbname); 

if($condition == 'con1'){
    $sql = "UPDATE users SET con1=? WHERE name=?";  
}elseif($condition == 'con2'){
    $sql = "UPDATE users SET con2=? WHERE name=?";  
}elseif($condition == 'con3'){
    $sql = "UPDATE users SET con3=? WHERE name=?";  
}

if($query = $conn->prepare($sql)) { 
    $query->bind_param($value,$name);
    $query->execute();

    print_r($query);

} else {
    $error = $conn->errno . ' ' . $conn->error;
    echo $error; 
}

然后我得到了那个错误:

Warning:  mysqli_stmt::bind_param(): Number of elements in type definition string doesn't match number of bind variables on line 32

$query

打印的内容
mysqli_stmt Object
(
[affected_rows] => -1
[insert_id] => 0
[num_rows] => 0
[param_count] => 2
[field_count] => 0
[errno] => 2031
[error] => No data supplied for parameters in prepared statement
[error_list] => Array
    (
        [0] => Array
            (
                [errno] => 2031
                [sqlstate] => HY000
                [error] => No data supplied for parameters in prepared statement
            )

    )

[sqlstate] => HY000
[id] => 1
)

有2个?和2个变量,我得到的错误是说参数的数量不等于变量的数量。

有什么问题?

1 个答案:

答案 0 :(得分:2)

在您的案例问题中,您是否使用了 - > bind_param函数错误。

// prepare and bind
$stmt = $conn->prepare("INSERT INTO MyGuests (firstname, lastname, email) VALUES (?, ?, ?)");
$stmt->bind_param("sss", $firstname, $lastname, $email); // sss means string string string

// set parameters and execute
$firstname = "John";
$lastname = "Doe";
$email = "john@example.com";
$stmt->execute();

论证可能是以下四种类型之一:

  • i - 整数
  • d - double
  • s - string
  • b - BLOB

我认为正确的代码应如下所示:

$conn = new mysqli($DB, $username, $password, $dbname); 

// You can avoid this structure, by doing concatenation!!!**
if($condition == 'con1'){
    $sql = "UPDATE users SET con1=? WHERE name=?";  
}elseif($condition == 'con2'){
    $sql = "UPDATE users SET con2=? WHERE name=?";  
}elseif($condition == 'con3'){
    $sql = "UPDATE users SET con3=? WHERE name=?";  
}

if($query = $conn->prepare($sql)) { 
    $query->bind_param("ss", $con, $name);
    $con = 'yourNeededValue';
    $name = 'someName?';
    $query->execute();

} else {
    $error = $conn->errno . ' ' . $conn->error;
    echo $error; 
}