Question

我尝试为String[]创建验证，如下所示，但我得到了例外。

11：28：02,832 WARN [http-nio-8080-exec-1] internal.ValidationExceptionMapper（ValidationExceptionMapper.java:119） - 意外的Bean验证问题。 javax.validation.UnexpectedTypeException：HV000030：找不到约束的验证器＆＃39; javax.validation.constraints.Pattern＆＃39;验证类型＆＃39;类java.lang.String []＆＃39;。检查配置

import javax.validation.Valid;
import javax.validation.constraints.Pattern;

/**
 * Created by vagrant on 3/16/18.
 */
public class ShareClassSearchRequest extends BaseSearchRequest
{
    private static final long serialVersionUID = 1L;

    @Valid
    private @Pattern(regexp = InputValidationPattern.REGULAR_TEXT)String[] legalNames;

    @Valid
    private @Pattern(regexp = InputValidationPattern.INTEGER)String[] investmentProductIds;

    public String[] getLegalNames()
    {
        return legalNames;
    }

    public void setLegalNames(String[] legalNames)
    {
        this.legalNames = legalNames;
    }

    public String[] getInvestmentProductIds()
    {
        return investmentProductIds;
    }

    public void setInvestmentProductIds(String[] investmentProductIds)
    {
        this.investmentProductIds = investmentProductIds;
    }
}

Answer 1

@Pattern无法应用于String[]。

相反，您可以使用List替换数组：

@Valid
private List<@Pattern(regexp = InputValidationPattern.REGULAR_TEXT) String> legalNames;

在java 7及更早版本中，您必须为String[]

创建自定义约束

javax.validation.constraints.Pattern验证类型类java.lang.String []

1 个答案: