Question

我有两种格式的日期值（6/13/2018和6-13-2018）。我不得不计算日期差异。以下是我的工作。

问题：少数项目的出现天数不正确。

X['Date of Closing'] = X['Date of Closing'].str.replace('/','-')
X['Date of First Contact'] = X['Date of First Contact'].str.replace('/','-')

X['Date Difference'] = (pd.to_datetime(X['Date of Closing'])- pd.to_datetime(X['Date of First Contact'])).dt.days

示例：

Date of First Contact  | Date of Giving Proposal  | Date of Closing  \
0             13-01-2014              26-02-2014      26-02-2014   
1             28-01-2014                2/2/2014        2-2-2014   
2              11-1-2014              26-01-2014      26-01-2014   
3             18-01-2014              18-01-2014      18-01-2014   
4             14-01-2014              14-01-2014      14-01-2014   
5               5-1-2014              14-01-2014      14-01-2014

输出：

44 - 正确

5 - 正确

-279 - 不正确

0 - 正确

0 - 正确

-107 - 不正确

Answer 1

我认为需要参数dayfirst=True或format：

X['Date Difference'] = (pd.to_datetime(X['Date of Closing'], dayfirst=True)- 
                        pd.to_datetime(X['Date of First Contact'], dayfirst=True)).dt.days

X['Date Difference'] = (pd.to_datetime(X['Date of Closing'], format='%d-%m-%Y')- 
                        pd.to_datetime(X['Date of First Contact'], format='%d-%m-%Y')).dt.days

print (X)
  Date of First Contact Date of Giving Proposal Date of Closing  \
0            13-01-2014              26-02-2014      26-02-2014   
1            28-01-2014                2/2/2014        2-2-2014   
2             11-1-2014              26-01-2014      26-01-2014   
3            18-01-2014              18-01-2014      18-01-2014   
4            14-01-2014              14-01-2014      14-01-2014   
5              5-1-2014              14-01-2014      14-01-2014   

   Date Difference  
0               44  
1                5  
2               15  
3                0  
4                0  
5                9

日期差异出现了错误 - Python

1 个答案: