Question

我正在使用RabbitMq来处理我在公交车上收到的消息。我想知道是否有更好的方法来处理我收到的消息（可能使用async/await模式）

以下是我的代码片段

connection = connectionFactory.CreateConnection();

channel = connection.CreateModel();

channel.QueueDeclare(queue: Constants.RabbitListeningQueue,durable: false,exclusive: false,autoDelete: false,arguments: null);
channel.QueueDeclare(queue: Constants.RabbitMqRequestInsertedQueue,durable: false,exclusive: false,autoDelete: false,arguments: null);

var consumer = new EventingBasicConsumer(channel);
consumer.Received += (model, ea) =>
{
    log.Debug($"[x] Received message :{ea}");
    var body = ea.Body;
    var message = Encoding.UTF8.GetString(body);

    var dynamicObject = JObject.Parse(message);

    queueMessageHandler.HandleMessage(dynamicObject);
};

queueMessageHandler实施如下

public class QueueMessageHandler : IQueueMessageHandler
{
    private readonly IImportNucleoManager importNucleoManager;

    public QueueMessageHandler(IImportNucleoManager importNucleoManager)
    {
        this.importNucleoManager = importNucleoManager;
    }

    public void HandleMessage(dynamic message)
    {
        switch ((string)message.Type)
        {
            case "T1":
            {
                importNucleoManager.Process(message);
                break;
            }
            case "T3":
                importNucleoManager.ProceedToInsertStep(message);
                break;
        }
    }
}

我想知道（因为T1 / T3事件需要很长时间才能处理），如果它们是Task，那么即使HandleMessage应该是HandleMessageAsync？在这种情况下，我还必须传递一个async void，这不是我所知道的最佳实践

Answer 1

static async Task Main(string[] args)
{
    var connectionFactory = new ConnectionFactory(DispatchConsumersAsync = true);
    var connection = connectionFactory.CreateConnection();
    var channel = connection.CreateModel();

    var consumer = new AsyncEventingBasicConsumer(channel);
    consumer.Received += Consumer_Received;
}

static async Task Consumer_Received(object sender, BasicDeliverEventArgs @event)
{
    await DoSomethingAsync();
}

RabbitMq Handle以异步方式接收消息

1 个答案: