Question

这是我的字符串：

www.stackoverflow.com/questions/ask/user/end

我将其与/分成一个单独的单词列表：myString.Split('/').ToList()

输出：

www.stackoverflow.com
questions
ask
user
end

我需要重新加入字符串以获得这样的列表：

www.stackoverflow.com
www.stackoverflow.com/questions
www.stackoverflow.com/questions/ask
www.stackoverflow.com/questions/ask/user
www.stackoverflow.com/questions/ask/user/end

我认为linq聚合但似乎它不适合这里。我想通过linq

完成所有这些

Answer 1

您可以尝试使用foreach迭代它

var splitted = "www.stackoverflow.com/questions/ask/user/end".Split('/').ToList();
string full = "";
foreach (var part in splitted)
{
    full=$"{full}/{part}"
    Console.Write(full);
}

或者使用linq：

var splitted = "www.stackoverflow.com/questions/ask/user/end".Split('/').ToList();
var list = splitted.Select((x, i) => string.Join("/", a.Take(i + 1)));

Answer 2

带有副作用的

Linq ：

  string prior = null;

  var result = "www.stackoverflow.com/questions/ask/user/end"
    .Split('/')
    .Select(item => prior == null
       ? prior = item
       : prior += "/" + item)
    .ToList();

让我们把它打印出来

  Console.WriteLine(string.Join(Environment.NewLine, result));

结果：

www.stackoverflow.com
www.stackoverflow.com/questions
www.stackoverflow.com/questions/ask
www.stackoverflow.com/questions/ask/user
www.stackoverflow.com/questions/ask/user/end

Answer 3

Linq没有副作用;）
如果我们使用Enumerable.Aggregate作为结果，则可以在此使用List<T>。

var raw = "www.stackoverflow.com/questions/ask/user/end";

var actual = 
    raw.Split('/')
       .Aggregate(new List<string>(),
                 (list, word) =>
                 {
                     var combined = list.Any() ? $"{list.Last()}/{word}" : word;
                     list.Add(combined);
                     return list;
                 });

Answer 4

没有Linq写下代码，

var str = "www.stackoverflow.com/questions/ask/user/end";
        string[] full = str.Split('/');
        string Result = string.Empty;

        for (int i = 0; i < full.Length; i++)
        {
            Console.WriteLine(full[i]);

        }
        for (int i = 0; i < full.Length; i++)
        {
            if (i == 0)
            {
                Result = full[i];
            }
            else
            {
                Result += "/" + full[i];
            }
            Console.WriteLine(Result);
        }

拆分然后逐步加入字符串 - C＃Linq

4 个答案: