我使用createQueryBuilder创建这样的查询
$result = $qb->select('csr.id,csr.survey')
->from('Entity\ClientSurveyRecord', 'csr')
->innerJoin('Entity\AbstractClientRecord','cr','WITH','cr.id = csr.id')
->innerJoin('Entity\Client','c','WITH','cr.client = c.id')
->where('csr.survey = :id_survey')
->setParameter('id_survey',$id)
->getQuery()
->getResult();
我收到以下消息类型:Doctrine \ ORM \ Query \ QueryException
Message: [Semantical Error] line 0, col 18 near 'survey FROM Entity\ClientSurveyRecord': Error: Invalid PathExpression. Must be a StateFieldPathExpression.
Filename: /var/www/vendor/doctrine/orm/lib/Doctrine/ORM/Query/QueryException.php
但如果我为$qb->select('csr.id,csr.survey')
更改了$qb->select('csr.id')
,那么
这是映射文件
Entity\ClientSurveyRecord:
type: entity
table: clients_survey_records
fields:
result:
type: integer
column: result
nullable: false
options:
comment: Client survey current result.
manyToOne:
survey:
targetEntity: Entity\AbstractSurvey
joinColumn:
name: id_survey
referenceColumnName: id
nullable: false
surveyShipmentTracking:
targetEntity: Entity\SurveyShipmentTracking
joinColumn:
name: id_survey_shipment_tracking
referenceColumnName: id
nullable: false
答案 0 :(得分:0)
您需要使用映射属性加入关系,例如需要在查询构建器对象中加入此关联的调查
$result = $qb->select(['csr.id','s']) // or add column names ['csr.id','s.id','s.title', ...]
->from('Entity\ClientSurveyRecord', 'csr')
->innerJoin('csr.survey','s')
->innerJoin('Entity\AbstractClientRecord','cr','WITH','cr.id = csr.id')
->innerJoin('Entity\Client','c','WITH','cr.client = c.id')
->where('s.id = :id_survey')
->setParameter('id_survey',$id)
->getQuery()
->getResult();
如果您使用一些映射属性加入Entity\AbstractClientRecord
和Entity\Client
也是一件好事,就像您已经为调查所做的那样,例如
$result = $qb->select(['csr.id','s'])
->from('Entity\ClientSurveyRecord', 'csr')
->innerJoin('csr.survey','s')
->innerJoin('csr.abstractClientRecord','cr')
->innerJoin('cr.client','c')
->where('s.id = :id_survey')
->setParameter('id_survey',$id)
->getQuery()
->getResult();