Question

我有这样的列表

John
   Jack 
       Husam 
   Koko 
       Rami 
       Loay

我有下拉列表它也有所有这些名字，当我输入Rami的id例如在URL中他在下拉列表中选择了选项时，我想如果我在URL中输入Rami的ID使他的父母（科科）选择的选项不是拉米。我构建函数来获取父ID及其工作如何从ajax调用它并获取id的父ID我在URL中输入

PHP

  public function getParentId($childId)
 {
    $statment = $this->db->prepare("SELECT parent FROM `person` WHERE id = $childId");
    $statment->execute();
    $result = $statment->fetchAll();

    foreach($result as $output){

        return $output['parent'];
    }

 }

这是我的ajax

if ($object->getParentId(($_GET['childId']))){
echo "<script>
$(document).ready(function(){
$.ajax({
type: 'GET', 
url: 'http://test.local/Family.php?action=getId&childId=idd',
data: {'idd' : $_GET[childId]},
success: function(msg) {
 document.getElementById('names').value = $_GET[childId];
  }
  });
   }); </script>";
 }

Answer 1

我改变了这部分

if ($object->getParentId(($_GET['childId']))){
echo "<script>
$(document).ready(function(){
$.ajax({
type: 'GET', 
url: 'http://test.local/Family.php?action=getId&childId=idd',
data: {'idd' : $_GET[childId]},
success: function(msg) {
document.getElementById('names').value = $_GET[childId];
}
});
 }); </script>";
 }

对此及其工作

if ($object->getParentId(($_GET['childId']))){
echo "<script>
$(document).ready(function(){
$.ajax({
type: 'GET', 
url: 'http://test.local/Family.php?action=getId',
data: {'childId' : $_GET[childId]},
success: function(msg) {
document.getElementById('names').value = msg;
}
});
}); </script>";
}

使用AJAX将变量发送到PHP并再次使用AJAX检索输出

1 个答案: