Question

我是学习python 3的初学者。我遇到了一个问题。请看三星内的代码：

s = input("Enter the value of N A B with white space in between ")
N, A, B=list(s.split())

def input_for_faces(*args):
    NumberOfA=0
    NumberOfB=0
    for x in args:
        if x == int(A):
            NumberOfA += 1
    for y in args:
        if y == int(B):
            NumberOfB += 1
    listAB=[NumberOfA, NumberOfB]
    return listAB

# ***
var=input("Enter the values on the faces of the cube seperated by commas ")
NA, NB=input_for_faces(var)
print(input_for_faces(var))
# ***

print("The probability of the chef winning is "+str((int(NA)/int(N)*(int(NB)/int(N))))

*args的这种输入方法没有给出正确的输出（它有效，但给出了错误的答案）。但是当我为args提供直接值时，程序运行正常。

直接输入是指：

s = input("Enter the value of N A B with white space in between ")
N, A, B=list(s.split())

def input_for_faces(*args):
    NumberOfA=0
    NumberOfB=0
    for x in args:
        if x == int(A):
            NumberOfA += 1
    for y in args:
        if y == int(B):
            NumberOfB += 1
    listAB=[NumberOfA, NumberOfB]
    return listAB

# ***
NA, NB=input_for_faces(1,1,1,1,1)
# ***

print("The probability of the chef winning is "+str((int(NA)/int(N))*(int(NB)/int(N))))

请告诉我我做错了什么。

Answer 1

1，在＆＃39; if＆＃39; 条件的本部分代码中，您将字符串与整数进行比较，以便条件变为false并且不计算 ＆＃39; NumberOfA＆＃39;

for x in args: if x == int(A): NumberOfA += 1 for y in args: if y == int(B): NumberOfB += 1 listAB=[NumberOfA, NumberOfB]

输出：

Enter the value of N A B with white space in between 1 1 1 Enter the values on the faces of the cube seperated by commas 1,1,1,1,1 [0, 0] The probability of the chef winning is 0.0 >>>

2，您将传递单个字符串作为 * args 的输入所以要传递多个参数，你将输入转换为列表 lvar = var.split（＆＃39;，＆＃39;），然后在函数调用中使用 * lvar {NA，NB = input_for_faces（* lvar）}，将从列表中逐个传递多个参数

s =输入（＆＃34;输入N A B的值，其间为空格＆＃34;）     N，A，B = list（s.split（））

def input_for_faces(*args): NumberOfA=0 NumberOfB=0 for x in args: if x == A: NumberOfA += 1 for y in args: if y == B: NumberOfB += 1 listAB=[NumberOfA, NumberOfB] return listAB # *** var=input("Enter the values on the faces of the cube seperated by commas ") lvar=var.split(',') NA, NB=input_for_faces(*lvar) print(input_for_faces(*lvar)) # *** print("The probability of the chef winning is "+str((int(NA)/int(N)*(int(NB)/int(N)))))

输出：

Enter the value of N A B with white space in between 1 1 1 Enter the values on the faces of the cube seperated by commas 1,1,1,1,1 [5, 5] The probability of the chef winning is 25.0

Answer 2

如果您不想或不必使用* args，您可以这样做：

s = raw_input("Enter the value of N A B with white space in between ")
N, A, B=list(s.split())

def input_for_faces(inputList):
    NumberOfA=0
    NumberOfB=0
#You only need to loop through once for A and B, no need to do each separately
#You can still use the old one though if you want to
    for number in inputList:
        if number == int(A):
            NumberOfA += 1
        if number == int(B):
            NumberOfB += 1
    listAB =[NumberOfA, NumberOfB]
    return listAB

var =raw_input("Enter the values on the faces of the cube seperated by commas: ").split(",")
inputList = [int(i) for i in var]
NA,NB = input_for_faces(inputList)
print(input_for_faces(inputList))
print("The probability of the chef winning is "+str((int(NA)/int(N))*(int(NB)/int(N))))

或使用* args：

s = raw_input("Enter the value of N A B with white space in between ")
N, A, B=list(s.split())

def input_for_faces(*args):
    NumberOfA=0
    NumberOfB=0
#You only need to loop through once for A and B, no need to do each separately
#You can still use the old one though if you want to
    for number in inputList:
        if number == int(A):
            NumberOfA += 1
        if number == int(B):
            NumberOfB += 1
    listAB =[NumberOfA, NumberOfB]
    return listAB

var =raw_input("Enter the values on the faces of the cube seperated by commas: ").split(",")
inputList = [int(i) for i in var]
NA,NB = input_for_faces(*inputList)
print(input_for_faces(*inputList))
print("The probability of the chef winning is "+str((int(NA)/int(N))*(int(NB)/int(N))))

用于计算数字重复次数的简单程序

2 个答案: