Question

当我使用有许多没有选择时，它返回userTrancastion表中的所有字段

Invoicemodule.php

$invoice = UserInvoiceDetail::with('transaction')
            ->select('Id','UserId','TotalPrice')
            ->where('UserId','=',$playerId)
            ->get();
            return $invoice;

UserInvoiceDetail.php

class UserInvoiceDetail extends Model
{
    protected $table = 'user_invoice_details';
    protected $primaryKey ='Id';
    public function transaction() 
    {
        return $this->hasMany(UserTransaction::class, 'InvoiceId');
    }
}

输出

"Invoices": 
[
        {
            "Id": 1,
            "UserId": 5,
            "TotalPrice": 110,
            "transaction": [
                {
                    "Id": 1,
                    "InvoiceId": 1,
                    "UserId": 5,
                    "ReferenceTransactionId": null,
                    "CategoryId": 1,
                    "ProductId": 140,
                    "Price": 5,
                    "Quantity": 5,
                    "CustomerId": 1,
                },
                {
                    "Id": 2,
                    "InvoiceId": 1,
                    "UserId": 5,
                    "ReferenceTransactionId": null,
                    "CategoryId": 2,
                    "ProductId": 3,
                    "Price": 15,
                    "Quantity": 3,
                    "CustomerId": 1,
                }
            ]
        }
]

但是当我使用有很多选项时，它不会返回任何userTrancastion表

UserInvoiceDetail.php

class UserInvoiceDetail extends Model
{
    protected $table = 'user_invoice_details';
    protected $primaryKey ='Id';

    public function transaction() 
    {
        return $this->hasMany(UserTransaction::class, 'InvoiceId')->select('user_transactions.Id','user_transactions.ProductId');
    }

}

输出

"Invoices": [
    {
        "Id": 1,
        "UserId": 5,
        "TotalPrice": 110,
        "transaction": []
    },
    {
        "Id": 2,
        "UserId": 5,
        "TotalPrice": 110,
        "transaction": []
    }
]

为什么会发生这种情况，我想在事务（）函数中使用join，所以我只需要选择性字段。如何使用hasmany（）选择？提前谢谢。

Answer 1

关系需要与之相关的列添加.Select(g => { var groupedDocuments = normalDocuments .Where(x => x.DetailId == g.Key.DetailId) .GroupBy(x => x.PersianMonth) .ToDictionary(x => x.Key, x => new DepositTypes(x.Sum(y=>y.Debit), x.Sum(y=>y.Credit)); Func<int, bool, decimal> getValueFunc = (id, isDebit) => groupedDocuments.TryGetValue(id, out var value) ? (isDebit ? value.Debit ?? value.Credit) : 0; return new AccountsAgingViewModel { DetailId = g.Key.DetailId, DetailCode = g.Key.DetailCode, DetailDescription = g.Key.DetailDescription, FarvardinDebit = getValueFunc(1, isDeposit: true); OrdibeheshtDebit = getValueFunc(2, isDeposit: true); // etc. }; } private class DepositTypes { public decimal Debit { get; } public decimal Credit {get; } public DepositTypes(decimal debit, decimal credit) { Debit = debit; Credit = credit; } } 此外，它不需要添加InvoiceId

user_transactions

Laravel hasmany函数什么都不返回

1 个答案: