将表格行移动到另一个表格并将其取回

时间：2018-06-13 02:31:18

标签： javascript jquery html css

我在下面有这个代码，允许我将值从Random Fruits Table移动到Green Fruits Table问题是我想尝试做到这一点，以便我移动该值后我想成为能够通过点击行的同样方式从Green Fruits Table获取该值，但我不希望Green Table的原始值可点击或受影响是否有任何简单的方法可以实现这个？非常感谢任何建议，谢谢。

var obj = {};
var obj2 = {};

var key = "Red Fruits";
obj[key] = ['Apple', 'Cherry', 'Strawberry'];
var myArray = [];
myArray.push(obj);

var key2 = "Green Fruits";
obj[key2] = ['Watermelon', 'Durian', 'Avacado'];
var myArray2 = [];
myArray2.push(obj);

var key3 = "Random Fruits";
obj2[key3] = ['Kiwi', 'Pomegranate', 'Honeydew', 'Plum'];
var myArray3 = [];
myArray3.push(obj2);

function redraw(obj) {

  var $header = $("<tr>"),
    cols = 0,
    bodyString = "";

  $.each(obj, function(key, values) {
    cols = Math.max(cols, values.length);
    $header.append($('<th/>').text(key + ": " + values.length));
  });
  for (var i = 0; i < cols; i++) {
    bodyString += '<tr>';
    $.each(obj, function(key, values) {
      bodyString += '<td>' +
        (values[i] ? values[i] : "") +
        '</td>';
    });
    bodyString += '</tr>';
  }
  $('.fruitsclass thead').html($header);
  $('.fruitsclass tbody').html(bodyString);
  var bodyString = '';
var headString = '';
$.each(obj2[key3], function(index) {
  bodyString += ('<tr><td>' + obj2[key3][index] + '</td></tr>');
});
headString += ('<tr><th>' + 'Random Fruits' + '</th></tr>');
$('.fruityclass tbody').html(bodyString);
$('.fruityclass thead').html(headString);
}


function listener(obj) {
  $(document).ready(function() {
    $("#fruityid td").click(function() {
      getval(this);
      data = this.innerHTML;
      k1 = Object.keys(obj2).find(k => obj2[k].indexOf(data) >= 0)
      index = obj2[k1].indexOf(data);
      obj2[k1].splice(index, 1);
      obj[key2].push(data);
      redraw(obj);
      listener(obj);
    });
  });
}

function getval(cel) {
 // alert(cel.innerHTML);
}
redraw(obj)
listener(obj);
.class {
  font-family: Open Sans;
}

.center {
  display: flex;
  justify-content: center
}

.skillsTable th {
  border-left: 1px solid #AAA5A4;
  border-right: 1px solid #AAA5A4;
}

table {
  float: left;
  border-collapse: collapse;
  width: 70%
}

td {
  border-left: 1px solid #AAA5A4;
  border-right: 1px solid #AAA5A4;
  padding-top: 8px;
  padding-left: 11px;
  font-size: 15px;
}

th {
  color: #0080ff;
  font-weight: normal;
  border-bottom: 1px solid #AAA5A4;
  padding-bottom: 5px;
}

div {
  margin-bottom: 50px;
}
<!DOCTYPE html>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<html>

  <head>
    <meta charset="utf-8" />
    <link rel="shortcut icon" href="//#" />

  </head>

  <body>
    <div id="result"> </div>
    <div class="center">
      <table id="fruitsid" class="fruitsclass skillsTable class">
        <thead></thead>
        <tbody></tbody>
      </table>
    </div>
    <div class="center">
      <table id="fruityid" class="fruityclass skillsTable class">
        <thead></thead>
        <tbody></tbody>
      </table>
    </div>
  </body>

</html>

2 个答案:

答案 0 :(得分：1)

每次向表中添加一行时都不需要调用重绘。

您需要像下面这样做，以便能够从绿色水果表中识别新添加的水果，

这就是你提问jsFiddle

的小提琴 

<a id="_ghidd" class="bh">TestLink </a>

 var obj = {};
var obj2 = {};

var key = "Red Fruits";
obj[key] = ['Apple', 'Cherry', 'Strawberry'];
var myArray = [];
myArray.push(obj);

var key2 = "Green Fruits";
obj[key2] = ['Watermelon', 'Durian', 'Avacado'];
var myArray2 = [];
myArray2.push(obj);

var key3 = "Random Fruits";
obj2[key3] = ['Kiwi', 'Pomegranate', 'Honeydew', 'Plum'];
var myArray3 = [];
myArray3.push(obj2);

function redraw(obj) {

  var $header = $("<tr>"),
    cols = 0,
    bodyString = "";

  $.each(obj, function(key, values) {
    cols = Math.max(cols, values.length);
    $header.append($('<th class="total_count_'+key.replace(/\s/g,'_')+'"/>').text(key + ": " + values.length));
  });
  for (var i = 0; i < cols; i++) {
    bodyString += '<tr>';
    $.each(obj, function(key, values) {
      bodyString += '<td>' +
        (values[i] ? values[i] : "") +
        '</td>';
    });
    bodyString += '</tr>';
  }
  $('.fruitsclass thead').html($header);
  $('.fruitsclass tbody').html(bodyString);
  var bodyString = '';
var headString = '';
$.each(obj2[key3], function(index) {
  bodyString += ('<tr><td>' + obj2[key3][index] + '</td></tr>');
});
headString += ('<tr><th>' + 'Random Fruits' + '</th></tr>');
$('.fruityclass tbody').html(bodyString);
$('.fruityclass thead').html(headString);
}


function addNewRow(fruitName) {
  var tds = '<tr><td class="new-row">' + + '</td></tr>';
}

function listener(obj) {
  $(document).ready(function() {
    $("#fruityid td").click(function() {
      getval(this);
      data = this.innerHTML;
      k1 = Object.keys(obj2).find(k => obj2[k].indexOf(data) >= 0)
      index = obj2[k1].indexOf(data);
      obj2[k1].splice(index, 1);
      obj[key2].push(data);
      $(".total_count_Green_Fruits").html(key2 + ': ' + obj[key2].length);
      var element = $(this).detach();
      $('#fruitsid > tbody').append('<tr><td></td><td class="new-green-fruit">'+element.html()+'</td></tr>'); //since we need to add to green fruit
      // now, if you want 
    });
  });
}


$('body').on('click', '.new-green-fruit', function() {
   alert("clicked on new green fruit : " + $(this).html());
});


function getval(cel) {
 // alert(cel.innerHTML);
}
redraw(obj);
listener(obj);
.class {
  font-family: Open Sans;
}

.center {
  display: flex;
  justify-content: center
}

.skillsTable th {
  border-left: 1px solid #AAA5A4;
  border-right: 1px solid #AAA5A4;
}

table {
  float: left;
  border-collapse: collapse;
  width: 70%
}

td {
  border-left: 1px solid #AAA5A4;
  border-right: 1px solid #AAA5A4;
  padding-top: 8px;
  padding-left: 11px;
  font-size: 15px;
}

th {
  color: #0080ff;
  font-weight: normal;
  border-bottom: 1px solid #AAA5A4;
  padding-bottom: 5px;
}

div {
  margin-bottom: 50px;
}

我所做的是，将td从随机水果桌上取下，并将其附在绿色水果桌上，上面有一个“新绿水果”类，这有助于区分新添加的tds与旧水果。< / p>

此外，我已经为新绿色水果tds注册了点击事件，因此只有在点击这些新水果时才会收到提醒

答案 1 :(得分：0)

由于你没有将水果移到绿色水果后进行分类，所以绿色水果的原始水果必须在绿色水果阵列中具有原始指数。您可以创建一个函数，通过单击（之前已经完成）将绿色水果移动到随机区域，同时检查水果的索引（索引＆gt; = 3）

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