我的程序没有显示正在排序的每个正确列表，比较数和除了气泡排序方法之外的分配数。我想我错过了重置输入字符串但无法找出重置输入的方法。 有没有办法在不同的排序方法中对一个输入进行排序。 这是我的代码：
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Arrays;
import java.util.Scanner;
/**
* Create a program that does head-to-head comparisons between four sorting
* methods: improved bubble sort; selection sort; insertion sort; and Shell
* sort.
*
*/
public class SortAlgorithms {
private static char tracing;
private static char list;
private static int numAsgn = 0;
private static int numComp = 0;
private static int size;
private static int min;
private static int max;
private static final Scanner KBD = new Scanner(System.in);
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.print("How many elements do you want in the list? ");
size = KBD.nextInt();
System.out.print("What are the smallest and largest values for lsit elements? ");
min = KBD.nextInt();
max = KBD.nextInt();
KBD.nextLine();
pause();
System.out.print("Would you like to see the list before it's sorted? ");
list = Character.toUpperCase(br.readLine().charAt(0));
System.out.print("Would you like to see the list as it's being sorted? ");
tracing = Character.toUpperCase(br.readLine().charAt(0));
pause();
sortNumbers();
}
// prompt the user and wait for them to press enter
private static void pause() {
System.out.print("\n...Press enter...");
KBD.nextLine();
System.out.println();
}
/**
* Sort a list of integer values, generated randomly.
*/
public static void sortNumbers() {
resetCounts();
Integer[] numbers = randomNumbers(size, min, max);
if (list == 'Y') {
System.out.println("Here is the list: " + Arrays.toString(numbers));
pause();
}
System.out.printf("\n%1s%25s%20s%20s\n", "Method", "#COMP", "#ASGN", "#OPS");
bubbleSort(numbers);
System.out.printf("%1s%25d%20d%20d\n", "Bubble", numComp, numAsgn, numAsgn + numComp);
selectionSort(numbers);
System.out.printf("%1s%22d%20d%20d\n", "Selection", numComp, numAsgn, numAsgn + numComp);
insertionSort(numbers);
System.out.printf("%1s%22d%20d%20d\n", "Insertion", numComp, numAsgn, numAsgn + numComp);
shellSort(numbers);
System.out.printf("%1s%26d%20d%20d\n", "Shell", numComp, numAsgn, numAsgn + numComp);
}
/**
* Reset the operation counts to zero.
*/
public static void resetCounts() {
numAsgn = 0;
numComp = 0;
}
/**
* Generate an array of random values.
*
* @param howMany the length of the list to be generated.
* @param lo the smallest value allowed in the list
* @param hi the largest value allowed in the list
*/
public static Integer[] randomNumbers(int size, int min, int max) {
int range = max - min + 1;
Integer[] result = new Integer[size];
for (int i = 0; i < size; ++i) {
result[i] = (int) (min + range * Math.random());
}
return result;
}
/**
* Perform bubble sort on the given array.
*
* @param a the array to sort.
*/
public static <T extends Comparable<? super T>>
void bubbleSort(T[] a) {
for (int i = a.length - 1; i > 0; --i) {
boolean elementSwapped = false;
//numComp++;
for (int j = 0; j < i; ++j) {
numComp++;
if (a[j].compareTo(a[j + 1]) > 0) {
numAsgn += 3;
T temp = a[j + 1];
a[j + 1] = a[j];
a[j] = temp;
elementSwapped = true;
}
}
if (!elementSwapped) {
break;
}
//if (tracing == 'Y') {
System.out.println("one more bubbled up: "
+ Arrays.toString(a));
//}
}
}
/**
* Perform insertion sort on the given array.
*
* @param a the array to sort.
*/
public static <T extends Comparable<? super T>>
void insertionSort(T[] a) {
for (int i = 0; i < a.length - 1; ++i) {
int p = i + 1;
T temp = a[p];
++numAsgn;
while (p > 0 && a[p - 1].compareTo(temp) > 0) {
++numComp;
a[p] = a[p - 1];
++numAsgn;
--p;
}
if (p > 0) {
++numComp; // count the last a[p-1] comparison
}
a[p] = temp;
++numAsgn;
//if (tracing == 'Y') {
System.out.println("one more inserted: " + Arrays.toString(a));
//}
}
}
/**
* Perform selection sort on the given array. if tracing, show the array
* after each selection round.
*
* @param a the array to sort
*/
public static <T extends Comparable<? super T>>
void selectionSort(T[] a) {
for (int i = 0; i < a.length - 1; ++i) {
int p = i;
++numAsgn;
for (int j = i + 1; j < a.length; ++j) {
++numComp;
if (a[j].compareTo(a[p]) < 0) {
p = j;
++numAsgn;
}
}
T temp = a[i];
a[i] = a[p];
a[p] = temp;
++numAsgn;
//if (tracing == 'Y') {
System.out.println("one more selected: " + Arrays.toString(a));
//}
}
}
/**
* Perform shell sort on the given array.
*
* @param a the array to sort.
*/
public static <T extends Comparable<? super T>>
void shellSort(T[] a) {
int gap = a.length / 2;
++numComp;
while (gap >= 1) {
if (gap % 2 == 0) {
++gap;
}
++numComp;
for (int i = gap; i < a.length; ++i) {
++numAsgn;
int p = i;
T temp = a[p];
++numComp;
while (p >= gap && a[p - gap].compareTo(temp) > 0) {
a[p] = a[p - gap];
p -= gap;
++numAsgn;
}
a[p] = temp;
++numAsgn;
}
//if (tracing == 'Y') {
System.out.println("...gap=" + gap + ": " + Arrays.toString(a));
// }
gap /= 2;
}
}
/**
* Calculate how many operations a list of the given length should take.
*
* @param numItems the number of elements in a list.
* @return the number of operations expected (on average) to sort that list
*/
private static int expect(int numItems) {
return (numItems * numItems + numItems) * 5 / 4;
}
}
答案 0 :(得分：1)
每次排序时，您都会覆盖数组numbers，因此bubbleSort是第一个排序方法，您只能看到它。每个连续的排序方法只对排序的数组进行操作。此外，由于您已将计数定义为成员变量，因此需要在每个方法之前调用resetCounts()以获得新计数。在将数组传递给每个排序方法之前复制数组，并重置计数应该解决这个问题。
System.out.printf("\n%1s%25s%20s%20s\n", "Method", "#COMP", "#ASGN", "#OPS");
resetCounts();
bubbleSort(Arrays.copyOf(numbers, numbers.length));
System.out.printf("%1s%25d%20d%20d\n", "Bubble", numComp, numAsgn, numAsgn + numComp);
resetCounts();
selectionSort(Arrays.copyOf(numbers, numbers.length));
System.out.printf("%1s%22d%20d%20d\n", "Selection", numComp, numAsgn, numAsgn + numComp);
resetCounts();
insertionSort(Arrays.copyOf(numbers, numbers.length));
System.out.printf("%1s%22d%20d%20d\n", "Insertion", numComp, numAsgn, numAsgn + numComp);
resetCounts();
shellSort(numbers);
System.out.printf("%1s%26d%20d%20d\n", "Shell", numComp, numAsgn, numAsgn + numComp);