我有一个带有两个密钥的JSON:id和name。我需要一种方法在我的集合(querys.project.name)上插入该ID,当它的名称和JSON上的匹配时。
我的JSON示例:
var projectsMysql = [
{
"id" : 1,
"name" : "Something"
},
{
"id" : 5,
"name" : "Something else"
},
{
"id" : 50,
"name" : "Some name"
}]
在我的收藏中大约有60个这样的文件:
{
"_id" : ObjectId("58e42bf30a34d641be6c25c2"),
"folio" : "R-666-69",
"alias_purchase" : "Deal",
"project" : {
"description" : "",
"name" : "Something else"
// "projectsMysql_id" : 5 THIS SHOULD BE PLACED HERE
},
}
我为Node.js编写了一个函数,但现在我需要在mongo shell上直接运行它,我读到我需要使用cursor.forEach()方法,但是我找不到办法来做到这一点,这个是我的功能:
projectsMysql
.forEach(function(project){
var query = {
name: project.name
}
db.getCollection('requests')
.find(query)
.exec(function(err, response){
if (err) {
return
}
if (response) {
db.getCollection('requests')
.update({id: response.id}, {$set: {
'project.projectsMysql_id': project.id
console.log("element inserted");
}})
.exec(function(err){
});
}
});
});
你能指出我正确的方向吗?
答案 0 :(得分:0)
您想要的是bulkWrite()
,而不是为update()
数组中的每个文档实际执行projectsMysql
,而是实际构建一个"单个"声明由"多个"发送到服务器并更新相应文档的更新:
db.getCollection('requests').bulkWrite(
projectsMysql.map(({ id, name }) =>
({ "updateOne": {
"filter": { "project.name": name },
"update": { "$set": { "project.id": id } }
}})
)
)
如果您希望"多个文件"要匹配条件,只需切换到updateMany
:
db.getCollection('requests').bulkWrite(
projectsMysql.map(({ id, name }) =>
({ "updateMany": {
"filter": { "project.name": name },
"update": { "$set": { "project.id": id } }
}})
)
)
你的数组已经在内存中了,所以没有任何意义可以做任何其他类型的#34;迭代"您只需将.map()
属性$set
放到updateOne
语句(或updateMany
)上,然后在一个语句中将它们全部发出。更新只会在有"匹配的情况下实际处理。确实存在要实际更新的地方,因为使用What is PECS (Producer Extends Consumer Super)?将保留现有值。
要证明,考虑这些文件:
{
"folio" : "R-666-69",
"alias_purchase" : "Deal",
"project" : {
"description" : "",
"name" : "Something else"
}
},
{
"folio" : "R-666-67",
"alias_purchase" : "Deal",
"project" : {
"description" : "",
"name" : "Some name"
}
},
{
"folio" : "R-666-68",
"alias_purchase" : "Deal",
"project" : {
"description" : "",
"name" : "Some name"
}
}
{
"folio" : "R-666-64",
"alias_purchase" : "Deal",
"project" : {
"description" : "",
"name" : "Something"
}
},
{
"folio" : "R-666-65",
"alias_purchase" : "Deal",
"project" : {
"description" : "",
"name" : "Different"
}
}
以下更新:
var projectsMysql = [
{
"id" : 1,
"name" : "Something"
},
{
"id" : 5,
"name" : "Something else"
},
{
"id" : 50,
"name" : "Some name"
}]
db.getCollection('requests').bulkWrite(
projectsMysql.map(({ id, name }) =>
({ "updateMany": {
"filter": { "project.name": name },
"update": { "$set": { "project.id": id } }
}})
)
)
返回响应:
{
"acknowledged" : true,
"deletedCount" : 0,
"insertedCount" : 0,
"matchedCount" : 4,
"upsertedCount" : 0,
"insertedIds" : {
},
"upsertedIds" : {
}
}
并相应地改变匹配的文件:
{
"_id" : ObjectId("5b206a48f7fa0c655d90157a"),
"folio" : "R-666-69",
"alias_purchase" : "Deal",
"project" : {
"description" : "",
"name" : "Something else",
"id" : 5
}
}
{
"_id" : ObjectId("5b206a48f7fa0c655d90157b"),
"folio" : "R-666-67",
"alias_purchase" : "Deal",
"project" : {
"description" : "",
"name" : "Some name",
"id" : 50
}
}
{
"_id" : ObjectId("5b206a48f7fa0c655d90157c"),
"folio" : "R-666-68",
"alias_purchase" : "Deal",
"project" : {
"description" : "",
"name" : "Some name",
"id" : 50
}
}
{
"_id" : ObjectId("5b206a48f7fa0c655d90157d"),
"folio" : "R-666-64",
"alias_purchase" : "Deal",
"project" : {
"description" : "",
"name" : "Something",
"id" : 1
}
}
{
"_id" : ObjectId("5b206a48f7fa0c655d90157e"),
"folio" : "R-666-65",
"alias_purchase" : "Deal",
"project" : {
"description" : "",
"name" : "Different"
}
}