我想要一个包含成分列表的表格,但也包含子食谱列表,例如:
#recipe yellow lemon juice
Ingredient unit cost quantity
1.Yellow lemon Kg 1.7 1
2.--suppose it has ingredient 2
3.--suppose it has ingredient 3
#recipe mayonnaise
Ingredient unit cost quantity
1.olive oil Lt $2.5 1
2.egg Kg $2.5 0.12
3.mustard Kg $1.59 0.01
4.salt Kg $.9 0.01
5.RECIPE yellow lemon juice Lt $1.9 1 ------------this one is a recipe
我怎么知道蛋黄酱配方使用黄柠檬汁配方? 我有以下,但不知道如何在食谱表中允许子récipes
现在情况可能是我有3个食谱A,B,C
而食谱A
有几个成分,但也包括食谱B
和C
Create table recipe
(
recipe_id int primary key,
recipe_name varchar(30)
);
Create table ingredient
(
ingredient_id int primary key,
ingredient_name varchar(30),
ingredient_cost float
);
Create table food_ingredient
(
fk_recipe int not null,
fk_ingredient int not null,
measure float,
unit_of_measurement varchar(30)
);
INSERT INTO ingredient VALUES
(1,'olive oil',2.5),
(2,'egg',2.5),
(3,'mustard',1.59),
(4,'salt',0.9),
(5,'lemon ingredient 1',1.9),
(6,'lemon ingredient 2',1.9),
(7,'lemon ingredient 3',1.9);
INSERT INTO recipe VALUES
(100,'Recipe lemon juice'),
(200,'Recipe MAYONNAIse');
INSERT INTO food_ingredient VALUES
(100,5,1.0,'Lt'),
(100,6,1.0,'Lt'),
(100,7,1.0,'Lt'),
(200,1,0.2,'Lt'),
(200,2,0.5,'Kg'),
(200,3,0.5,'Kg'),
(200,4,0.2,'Kg'),
(200,5,1,'Lt');
答案 0 :(得分:0)
我可能会添加一个:
def get_comment_status(row):
if row['address'] == 'NY':
return ['call tomorrow', 'interview scheduled']
else:
return ['Dont call', 'application rejected']
df[['comment', 'selection_status']] = df.apply(get_comment_status, axis=1).values.tolist()
print(df)
address name1 name2 comment score selection_status
0 NY john mayer call tomorrow 90 interview scheduled
1 CA mayer dylan Dont call 8 application rejected
2 NJ dylan mayer Dont call 88 application rejected
3 NY bob bob call tomorrow 72 interview scheduled
4 WS mary bob Dont call 34 application rejected
5 OR jake tim Dont call 95 application rejected
6 OR rob ben Dont call 50 application rejected
我还要在我的蛋黄酱中添加一些糖和醋...... :)。