Question

我正在使用一个简单的表单，使用下面的PHP从数据库返回值，如何在行中返回其他值？

目前它正在返回产品ID，我也希望返回产品名称和描述。

<?php
$db = new mysqli("localhost", "root", "", "master");
if (isset($_GET['keywords'])) {
    $keywords = $db->escape_string($_GET['keywords']);
    $query    = $db->query("
            SELECT productID, productName
            FROM promo
            WHERE productID LIKE '%{$keywords}%'
            OR productID LIKE '%{$keywords}%'
        ");
?>

   <div class="resul-count">
    Found <?php
    echo $query->num_rows;
?> Results.
    </div>

    <?php
    if ($query->num_rows) {
        while ($r = $query->fetch_object()) {
?>
               <div class="result">
                    <a href="#"><?php
            echo $r->productID;
?></a>
                </div>
            <?php
        }
    }
}
?>

<html>

<head>
  <title>Search</title>
</head>

<body>
  <form action="./search.php" method="get">

    <label>Search By Product ID:
		<input type="text" name="keywords">
	</label>
    <input type="submit" value="search" autocomplete="off">
  </form>
</body>

</html>

Answer 1

首先，如果您希望它返回如下所示的值，则需要将产品描述添加到select语句中：

<?php
$db = new mysqli("localhost", "root", "", "master");
if (isset($_GET['keywords'])) {
    $keywords = $db->escape_string($_GET['keywords']);
    $query    = $db->query("
            SELECT productID, productName, productDescription 
            FROM promo

接下来，这个WHERE子句是多余的。您使用相同的搜索搜索每个项目两次

            WHERE productID LIKE '%{$keywords}%'
           // OR productID LIKE '%{$keywords}%' -- redundant code. same as the first test. 
        ");
?>

   <div class="resul-count">
    Found <?php echo $query->num_rows;?> 
    Results.
    </div>

    <?php
    if ($query->num_rows) {
        while ($r = $query->fetch_object()) {
    ?>
    <div class="result">
       <a href="#"><?php
       echo $r->productID;

最后你只是回应了产品ID。如果你想要其他两个项目，你需要回复它们：

       echo $r->productName;
       echo $r->productDescription;
       ?></a>
    </div>
     <?php
        }
    }
}
?>

将所有这些放在一起：

<?php
    $db = new mysqli("localhost", "root", "", "master");
    if (isset($_GET['keywords'])) {
        $keywords = $db->escape_string($_GET['keywords']);
        $query    = $db->query("
                SELECT productID, productName, productDescription 
                FROM promo
                WHERE productID LIKE '%{$keywords}%'
               // OR productID LIKE '%{$keywords}%' -- redundant code. same as the first test. 
            ");
?>
<div class="resul-count">
    Found <?php echo $query->num_rows;?> 
    Results.
</div>

<?php
    if ($query->num_rows) {
        while ($r = $query->fetch_object()) {
?>
<div class="result">
    <a href="#">
        <?php
            echo $r->productID; 
            echo $r->productName;
            echo $r->productDescription;
        ?>
    </a>
</div>
<?php
            }
        }
    }
?>

从搜索中返回其他列数据

1 个答案: