Question

输入：

1,aaaa,2018-11-03
2,bbbb,2018-02-03

预期输出

脚本应将日期视为MST7MDT格式并将其转换为UTC：

1,aaaa,2018-11-03 06:00:00
2,bbbb,2018-02-03 07:00:00

Answer 1

您没有指定您的操作系统。假设你有GNU日期：

(
    IFS=,
    while read -ra fields; do 
        t=$(TZ=America/Denver date -d "${fields[-1]}" "+%s")
        fields[-1]=$(TZ=UTC date -d "@$t" "+%F %T")
        echo "${fields[*]}"
    done
) <<END
1,aaaa,2018-11-03
2,bbbb,2018-02-03
END

1,aaaa,2018-11-03 06:00:00
2,bbbb,2018-02-03 07:00:00

我喜欢Perl的DateTime图书馆生态系统：

perl -E '
    use DateTime::Format::Strptime;
    my $dateparser = DateTime::Format::Strptime->new(
        pattern   => "%Y-%m-%d",
        time_zone => "America/Denver"
    );
    while (<>) {
        chomp;
        my @fields = split /,/;
        my $datetime = $dateparser->parse_datetime( $fields[-1] );
        $fields[-1] = $datetime->set_time_zone("UTC")->strftime("%Y-%m-%d %T");
        say join ",", @fields;
    }
' <<END
1,aaaa,2018-11-03
2,bbbb,2018-02-03
END

Answer 2

使用以下代码

工作正常

#!/bin/bash 
file=myfile 
while IFS= read -r line 
do 
csid=$(echo $line | cut -f1 -d,) 
name=$(echo $line | cut -f2 -d,) 
oldmt=$(echo $line | cut -f3 -d,) 
echo "$csid"",""$name"","$(date -u -d "TZ=\"MST7MDT\" $oldmt" "+%Y-%m-%d %H:%M:%S") >> newmyfile.dat    done < $file

SHELL将文件中的更新日期列更新为时间戳

2 个答案: