有没有办法在执行方法中访问插件属性?
我有一个基础mojo,它有一些属性,如:
@Parameter(defaultValue = "DEV", property = "dbEnvironment", required = true)
protected Environment dbEnvironment;
@Parameter(defaultValue = "true", property = "validate")
protected boolean validate;
然后,孩子mojo会添加一些额外的属性。我希望能够阅读所有这些属性,以验证它们,但是如何做到这一点并不明显。当我运行它时,通过调试,我看到了:
[DEBUG] Configuring mojo 'com.company.tools:something-maven-plugin:0.2.11-SNAPSHOT:export-job' with basic configurator -->
[DEBUG] (f) dbEnvironment = DEV
[DEBUG] (f) jobName = scrape_extract
[DEBUG] (f) project = MavenProject: com.company.tools:something-maven-plugin-it:1.0-SNAPSHOT @ /Users/selliott/intellij-workspace/tools-something-maven-plugin/something-maven-plugin/src/it/simple-it/pom.xml
[DEBUG] (f) session = org.apache.maven.execution.MavenSession@3fd2322d
[DEBUG] (f) validate = true
[DEBUG] -- end configuration --
所以,看起来这些道具在哪里,但在哪里?我试过从会话中获取它们,session.settings,session.request无济于事。
答案 0 :(得分:1)
好的,经过大量调试后,我能够根据AbstractConfigurationConverter的工作原理,特别是fromExpression方法来解决这个问题。
要获取属性,您需要在mojo中添加以下内容:
@Parameter(defaultValue = "${session}")
protected MavenSession session;
@Parameter(defaultValue = "${mojoExecution}")
protected MojoExecution mojoExecution;
从那里,你现在可以创建一个评估器和配置(也许你可以直接注入它们,我不确定),你可以这样做:
PluginParameterExpressionEvaluator expressionEvaluator = new PluginParameterExpressionEvaluator(session, mojoExecution);
PlexusConfiguration pomConfiguration = new XmlPlexusConfiguration(mojoExecution.getConfiguration());
for (PlexusConfiguration plexusConfiguration : pomConfiguration.getChildren()) {
String value = plexusConfiguration.getValue();
String defaultValue = plexusConfiguration.getAttribute("default-value");
try {
String evaluated = defaultIfNull(expressionEvaluator.evaluate(defaultIfBlank(value, defaultValue)), "").toString();
System.out.println(plexusConfiguration.getName() + " -> " + defaultIfBlank(evaluated, defaultValue));
} catch (ExpressionEvaluationException e) {
e.printStackTrace();
}
}