我是sql菜鸟,我不知道如何继续这个查询。
我有这张表m2AndPrices。它包含资产及其表面和价值相关。
|---------------------------------------------|
|id | code | m2 | value |
|---------------------------------------------|
|32980 | 143452asd10 | 11.17 | 0 |
|---------------------------------------------|
|25107 | 20152fgg219 | 57.00 | 55304,99 |
|---------------------------------------------|
|5692 | 203hhh75735 | 87.18 | 98334,16 |
|---------------------------------------------|
|31500 | 200788fgfg193 | 240.64 | 164401,75 |
|---------------------------------------------|
按平方米(m2)分组并进行计数我得到此输出:
|----------------------------------|
|m2section | number_of_assets |
|----------------------------------|
|<1 | 175 |
|----------------------------------|
|1-5 | 286 |
|----------------------------------|
|5-10 | 374 |
|----------------------------------|
|10-20 | 573 |
|----------------------------------|
|20-40 | 5212 |
|----------------------------------|
|40-80 | 3892 |
|----------------------------------|
|80-120 | 4121 |
|----------------------------------|
|120-180 | 1849 |
|----------------------------------|
|180-250 | 705 |
|----------------------------------|
|250-500 | 430 |
|----------------------------------|
| >500 | 131 |
|----------------------------------|
代码:
SELECT * FROM (
SELECT cast(m2section as varchar), COUNT(*) as number_of_assets FROM (
SELECT
CASE
WHEN m2 <= 1 THEN '<1'
WHEN m2 > 1 AND m2 <= 5 THEN '1-5'
WHEN m2 > 5 AND m2 <= 10 THEN '5-10'
WHEN m2 > 10 AND m2 <= 20 THEN '10-20'
WHEN m2 > 20 AND m2 <= 40 THEN '20-40'
WHEN m2 > 40 AND m2 <= 80 THEN '40-80'
WHEN m2 > 80 AND m2 <= 120 THEN '80-120'
WHEN m2 > 120 AND m2 <= 180 THEN '120-180'
WHEN m2 > 180 AND m2 <= 250 THEN '180-250'
WHEN m2 > 250 AND m2 <= 500 THEN '250-500'
WHEN m2 > 500 THEN '>500' END AS m2section
FROM (select * from m2AndPrices x) as a
) as A
GROUP BY m2section) as B
order by CASE
WHEN m2section = '<1' THEN 1
WHEN m2section = '1-5' THEN 2
WHEN m2section = '5-10' THEN 3
WHEN m2section = '10-20' THEN 4
WHEN m2section = '20-40' THEN 5
WHEN m2section = '40-80' THEN 6
WHEN m2section = '80-120' THEN 7
WHEN m2section = '120-180' THEN 8
WHEN m2section = '180-250' THEN 9
WHEN m2section = '250-500' THEN 10
WHEN m2section = '>500' THEN 11
END
;
很抱歉,如果它没有缩进。
我需要获取另一列,计算每个范围内元素数量的值,如:
|------------------------------------------------------|
|m2section | number_of_assets | total value ($)
|------------------------------------------------------|
|<1 | 175 | 345.436
|------------------------------------------------------|
|1-5 | 286 | 864.364
|------------------------------------------------------|
|5-10 | 374 | 364.334
|------------------------------------------------------|
|10-20 | 573 | 1.364.364
|------------------------------------------------------|
|20-40 | 5212 | 8.364.364
|------------------------------------------------------|
|40-80 | 3892 | 6.364.364
|------------------------------------------------------|
|80-120 | 4121 | .....
|------------------------------------------------------|
|120-180 | 1849 | .....
|------------------------------------------------------|
|180-250 | 705 | .....
|------------------------------------------------------|
|250-500 | 430 | .....
|------------------------------------------------------|
| >500 | 131 | .....
|------------------------------------------------------|
但我不知道在哪里可以计算价值($)。
任何想法都会被贬低。
非常感谢
答案 0 :(得分:1)
在Postgres中,我建议:
SELECT (CASE WHEN m2 <= 1 THEN '<1'
WHEN m2 > 1 AND m2 <= 5 THEN '1-5'
WHEN m2 > 5 AND m2 <= 10 THEN '5-10'
WHEN m2 > 10 AND m2 <= 20 THEN '10-20'
WHEN m2 > 20 AND m2 <= 40 THEN '20-40'
WHEN m2 > 40 AND m2 <= 80 THEN '40-80'
WHEN m2 > 80 AND m2 <= 120 THEN '80-120'
WHEN m2 > 120 AND m2 <= 180 THEN '120-180'
WHEN m2 > 180 AND m2 <= 250 THEN '180-250'
WHEN m2 > 250 AND m2 <= 500 THEN '250-500'
WHEN m2 > 500 THEN '>500'
END) AS m2section,
COUNT(*) as num_assets,
SUM(value) as sum_value
FROM m2AndPrices mp
GROUP BY m2section
ORDER BY MIN(m2);
现在,我还将简化CASE
表达式:
SELECT (CASE WHEN m2 <= 1 THEN '<1'
WHEN m2 <= 5 THEN '1-5'
WHEN m2 <= 10 THEN '5-10'
WHEN m2 <= 20 THEN '10-20'
WHEN m2 <= 40 THEN '20-40'
WHEN m2 <= 80 THEN '40-80'
WHEN m2 <= 120 THEN '80-120'
WHEN m2 <= 180 THEN '120-180'
WHEN m2 <= 250 THEN '180-250'
WHEN m2 <= 500 THEN '250-500'
WHEN m2 > 500 THEN '>500'
END) AS m2section,
COUNT(*) as num_assets,
SUM(value) as sum_value
FROM m2AndPrices mp
GROUP BY m2section
ORDER BY MIN(m2);
注意:
CASE
表达式按顺序进行评估(保证),因此您不需要AND
表达式。GROUP BY
中使用列别名。强烈建议使用列别名而不是列号,因为后者在最新版本的SQL标准中已弃用。ORDER BY
有点诡计,但它会按m2
值排序,这正是您真正想要的。COUNT(*)
是合适的。如果你有重复项,那么你需要COUNT(DISTINCT)
,但是DISTINCT
会产生开销,所以除非必要,否则不要使用它。答案 1 :(得分:0)
如果您只使用一个原始表格,我认为您可以在此处大量简化查询? M2ANDPrices
首先,你要按m2分类,对吧?
SELECT
CASE
WHEN m2 <= 1 THEN '<1'
WHEN m2 > 1 AND m2 <= 5 THEN '1-5'
WHEN m2 > 5 AND m2 <= 10 THEN '5-10'
WHEN m2 > 10 AND m2 <= 20 THEN '10-20'
WHEN m2 > 20 AND m2 <= 40 THEN '20-40'
WHEN m2 > 40 AND m2 <= 80 THEN '40-80'
WHEN m2 > 80 AND m2 <= 120 THEN '80-120'
WHEN m2 > 120 AND m2 <= 180 THEN '120-180'
WHEN m2 > 180 AND m2 <= 250 THEN '180-250'
WHEN m2 > 250 AND m2 <= 500 THEN '250-500'
WHEN m2 > 500 THEN '>500'
END AS m2section
FROM m2AndPrices
GROUP BY 1 -- you can group by giving the index of the columns in the SELECT statement
这是起点。现在,如果要计算行数,请使用COUNT。为了安全起见,最佳做法是执行COUNT(DISTINCT id),这样就不会重复计算任何重复项。在您的情况下,计算销售数量或表格中的任何内容将为COUNT(DISTINCT id)
如果要获取总值,请使用SUM。所以你要做SUM(total_value)
完整代码:
SELECT
CASE
WHEN m2 <= 1 THEN '<1'
WHEN m2 > 1 AND m2 <= 5 THEN '1-5'
WHEN m2 > 5 AND m2 <= 10 THEN '5-10'
WHEN m2 > 10 AND m2 <= 20 THEN '10-20'
WHEN m2 > 20 AND m2 <= 40 THEN '20-40'
WHEN m2 > 40 AND m2 <= 80 THEN '40-80'
WHEN m2 > 80 AND m2 <= 120 THEN '80-120'
WHEN m2 > 120 AND m2 <= 180 THEN '120-180'
WHEN m2 > 180 AND m2 <= 250 THEN '180-250'
WHEN m2 > 250 AND m2 <= 500 THEN '250-500'
WHEN m2 > 500 THEN '>500'
END AS m2section,
COUNT(DISTINCT id) AS number_of_assets_per_m2_band,
SUM(total_value) AS total_value_per_m2_band
FROM m2AndPrices
GROUP BY 1 -- you can group by giving the index of the columns in the SELECT statement
ORDER BY 1 DESC;