Question

我试图找出如何仅在此数组中输出超过30秒的唯一ID。为了简单起见，只需要在30秒内获取第一个值以获得唯一ID。

$array = array(
0 => array(
    'id' => '1',
    'seconds' => '36'
),
1 => array(
    'id' => '1',
    'seconds' => '60'
),
2 => array(
    'id' => '1',
    'seconds' => '36'
),
3 => array(
    'id' => '2',
    'seconds' => '22'
),
4 => array(
    'id' => '1',
    'seconds' => '36'
),
5 => array(
    'id' => '2',
    'seconds' => '36'
),
6 => array(
    'id' => '3',
    'seconds' => '44'
),
7 => array(
    'id' => '3',
    'seconds' => '2'
),
8 => array(
    'id' => '4',
    'seconds' => '58'
),
9 => array(
    'id' => '6',
    'seconds' => '9'
),
10 => array(
    'id' => '6',
    'seconds' => '8'
));

理想的结果看起来像这样

$arrayResult = array(
0 => array(
    'id' => '1',
    'seconds' => '36'
),
1 => array(
    'id' => '2',
    'seconds' => '36'
),
2 => array(
    'id' => '3',
    'seconds' => '44'
),
3 => array(
    'id' => '4',
    'seconds' => '58'
));

目前，我只能获取ID的唯一值，而不会将秒与“ID”相关联。字段。

Answer 1

您可以使用array_reduce来迭代$array并仅提取您想要的值。

$array = array_reduce($array, function ($unique, $entry) {
    extract($entry);

    if (! isset($unique[$id]) && $seconds > 30) {
        $unique[$id] = $entry;
    }

    return $unique;
}, []);

$array = array_values($array);

Answer 2

$final_array = array();

foreach($array as $val)
{
    if($val['seconds'] > 30 && (!array_key_exists($val['id'], $final_array))){
        $final_array[$val['id']] = $val;
    }
}
echo "<pre>";
    print_r($final_array);
echo "</pre>";

如果要重置数组键，则可以使用

$final_array = array_values($final_array);

echo "<pre>";
    print_r($final_array);
echo "</pre>";

仅在PHP中显示大于x秒的唯一ID

2 个答案: