try {
JSONObject jobj = new JSONObject(response);
String status = jobj.getString("status");
String error = jobj.getString("result");
if(status == "1"){
builder.setTitle("Server Message");
builder.setMessage("Please validate your ID in registered email.");
}else if(status == "0")
{
builder.setTitle("Server Message");
builder.setMessage(error);
}else{
builder.setTitle("Server Message");
builder.setMessage(response);
}
} catch (JSONException e) {
e.printStackTrace();
}
builder.setPositiveButton("OK", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
Intent mainIntent = new Intent(RegisterActivity.this, LoginActivity.class);
startActivity(mainIntent);
}
});
AlertDialog alertDialog = builder.create();
alertDialog.show();
}
我的回答是{"状态":" 1","结果":" true") 但是我无法做到" status"意味着我无法获得" 1"在状态内。
答案 0 :(得分:3)
两个错误
==
这样做
int status = jobj.getInt("status");
Boolean error = jobj.getBoolean("result");
if(status == 1){
builder.setTitle("Server Message");
builder.setMessage("Please validate your ID in registered email.");
}else if(status == 0)
{
...
...
答案 1 :(得分:1)
我希望这对你有用。
使用String
String status = jobj.getString("status");
String error = jobj.getString("result");
if(status.equalsIgnoreCase("1")){
builder.setTitle("Server Message");
builder.setMessage("Please validate your ID in registered email.");
}else if(status.equalsIgnoreCase("0")){
// your other code.
}
答案 2 :(得分:0)
" =="是参考比较。 所以,替换" =="等于()
status.equals("1")