是否可以在列表项上使用CSS伪类?
我希望以下内容能够生成交替颜色的列表,但我会得到一个蓝色项目列表:
<html>
<head>
<style>
li { color: blue }
li:odd { color:green }
li:even { color:red }
</style>
</head>
<body>
<ul>
<li>ho</li>
<li>ho</li>
<li>ho</li>
<li>ho</li>
<li>ho</li>
</ul>
</body>
</html>
答案 0 :(得分:575)
演示:http://jsfiddle.net/thirtydot/K3TuN/1323/
li {
color: black;
}
li:nth-child(odd) {
color: #777;
}
li:nth-child(even) {
color: blue;
}
<ul>
<li>ho</li>
<li>ho</li>
<li>ho</li>
<li>ho</li>
<li>ho</li>
</ul>
文档:
答案 1 :(得分:42)
CSS的问题在于伪类的语法。
偶数和奇数伪类应该是:
li:nth-child(even) {
color:green;
}
和
li:nth-child(odd) {
color:red;
}
答案 2 :(得分:18)
使用此:
li { color:blue; }
li:nth-child(odd) { color:green; }
li:nth-child(even) { color:red; }
有关浏览器支持的信息,请参阅此处: http://kimblim.dk/css-tests/selectors/
答案 3 :(得分:3)
li:nth-child(1n) { color:green; }
li:nth-child(2n) { color:red; }
<ul>
<li>list element 1</li>
<li>list element 2</li>
<li>list element 3</li>
<li>list element 4</li>
</ul>
请在此处查看浏览器支持: CSS3 :nth-child() Selector
答案 4 :(得分:0)
css的奇数和偶数不支持IE。 建议您使用下面的解决方案。
最佳解决方案:
li:nth-child(2n+1) { color:green; } // for odd
li:nth-child(2n+2) { color:red; } // for even
li:nth-child(1n) { color:green; }
li:nth-child(2n) { color:red; }
<ul>
<li>list element 1</li>
<li>list element 2</li>
<li>list element 3</li>
<li>list element 4</li>
</ul>
答案 5 :(得分:0)
,但是在IE中不起作用。 建议使用 :nth-child(2n + 1) :nth-child(2n + 2)
li {
color: black;
}
li:nth-child(odd) {
color: #777;
}
li:nth-child(even) {
color: blue;
}
<ul>
<li>ho</li>
<li>ho</li>
<li>ho</li>
<li>ho</li>
<li>ho</li>
</ul>
答案 6 :(得分:0)
:nth-child(n)选择器匹配作为父元素的第n个子元素的每个元素(无论类型如何)。 奇数和偶数是关键字,可用于匹配索引为奇数或偶数(第一个孩子的索引为1)的子元素。
这就是您想要的:
<html>
<head>
<style>
li { color: blue }<br>
li:nth-child(even) { color:red }
li:nth-child(odd) { color:green}
</style>
</head>
<body>
<ul>
<li>ho</li>
<li>ho</li>
<li>ho</li>
<li>ho</li>
<li>ho</li>
</ul>
</body>
</html>
答案 7 :(得分:-1)
下面是偶数和奇数css颜色应用的示例
<html>
<head>
<style>
p:nth-child(even) {
background: red;
}
p:nth-child(odd) {
background: green;
}
</style>
</head>
<body>
<p>The first Odd.</p>
<p>The second Even.</p>
<p>The third Odd.</p>
<p>The fourth Even.</p>
</body>
</html>
答案 8 :(得分:-2)
<ul class="names" id="names_list">
<a href="javascript:void(0);"><span class="badge">1</span><li class="part1" id="1">Ashwin Nair</li></a>
<a href="javascript:void(0);"><span class="badge">2</span><li class="part2" id="2">Anil Reddy</li></a>
<a href="javascript:void(0);"><span class="badge">0</span><li class="part1" id="3">Chirag</li></a>
<a href="javascript:void(0);"><span class="badge">0</span><li class="part2" id="4">Ashwin</li></a>
<a href="javascript:void(0);"><span class="badge">0</span><li class="part1" id="15">Ashwin</li></a>
<a href="javascript:void(0);"><span class="badge">0</span><li class="part2" id="16">Ashwin</li></a>
<a href="javascript:void(0);"><span class="badge">5</span><li class="part1" id="17">Ashwin</li></a>
<a href="javascript:void(0);"><span class="badge">6</span><li class="part2" id="18">Ashwin</li></a>
<a href="javascript:void(0);"><span class="badge">1</span><li class="part1" id="19">Ashwin</li></a>
<a href="javascript:void(0);"><span class="badge">2</span><li class="part2" id="188">Anil Reddy</li></a>
<a href="javascript:void(0);"><span class="badge">0</span><li class="part1" id="111">Bhavesh</li></a>
<a href="javascript:void(0);"><span class="badge">0</span><li class="part2" id="122">Ashwin</li></a>
<a href="javascript:void(0);"><span class="badge">0</span><li class="part1" id="133">Ashwin</li></a>
<a href="javascript:void(0);"><span class="badge">0</span><li class="part2" id="144">Ashwin</li></a>
<a href="javascript:void(0);"><span class="badge">5</span><li class="part1" id="199">Ashwin</li></a>
<a href="javascript:void(0);"><span class="badge">6</span><li class="part2" id="156">Ashwin</li></a>
<a href="javascript:void(0);"><span class="badge">1</span><li class="part1" id="174">Ashwin</li></a>
</ul>
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var accc="#"+ac2;
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