Question

我可以请求我的代码帮助。它适用于Animal类，用户可以在其中输入一组身体部位的描述。我相信，我已正确初始化了数据成员和类方法。在void create（）方法中，当我运行程序时，提示符，第一个没有出现除了那个提示之外，它都在工作。

这是代码：

#include <iostream>
#include <string>
using namespace std;

class Animal{
    char birth[20];
    char legs[20];
    char eyes[20];
    char ears[20];
    char mouth[20];
    char nose[20];
    public:
    void create(){
        cout<<"Describe your animal"<<endl;

        cout<"Which animal are you?: ";
        cin.getline(birth, 20);
        cout<<"Could you describe your legs?: ";
        cin.getline(legs, 20);
        cout<<"How good are your eyes?: ";
        cin.getline(eyes, 20);
        cout<<"And your sense of hearing?: ";
        cin.getline(ears, 20);
        cout<<"Can i know what your mouth looks like?: ";
        cin.getline(mouth, 20);
        cout<<"Lastly I'd like to about your nose: ";
        cin.getline(nose, 20);
        cout<<endl;
        cout<<"I am a "<<birth<<endl;
    };
    void move(){
        cout<<"My legs are "<<legs<<endl;
    };
    void see(){
        cout<<"My eyes are "<<eyes<<endl;
    };
    void hear();
    void eat();
    void smell();
};

void Animal::hear(){
    cout<<"My hearing is "<<ears<<endl;
}
void Animal::eat(){
    cout<<"My mouth is "<<mouth<<endl;
}
void Animal::smell(){
    cout<<"My nose is "<<nose<<endl;
}

int main(){
    cout<<"\tDescribe Animal Chareteristics"<<endl<<endl;

    Animal eagle;
    eagle.create();
    eagle.move();
    eagle.hear();
    eagle.eat();
    eagle.smell();

}

当我跑的时候会跳过“你是哪个动物”的提示。我不知道，我想我错过了什么，这就是为什么它会被跳过

感谢您的帮助

Answer 1

该线路上的cout后，你的左尖括号丢失了。

C ++：跳过第一个用户输入提示

1 个答案: