Spring使用JWT auth,获取当前用户

时间:2018-06-11 18:09:31

标签: java spring spring-security jwt

我有Spring Boot REST应用程序,它使用JWT令牌进行授权。我想使用@AuthenticationPrincipal注释在控制器中获取当前记录的用户。但是如果我从null返回自定义模型并且auth停止工作,它总是返回loadUserByUsername。我的模型实现了UserDetails

我尝试扩展org.springframework.security.core.userdetails.User,但我摆脱 JWTAuthenticationFilter 错误,默认构造函数不存在(ApplicationUser creds = new ObjectMapper().readValue(req.getInputStream(), ApplicationUser.class);

怎么了?

UserDetailsS​​erviceImpl.java

@Service
public class UserDetailsServiceImpl implements UserDetailsService {
    private UserRepository userRepository;

    public UserDetailsServiceImpl(UserRepository userRepository) {
        this.userRepository = userRepository;
    }

    @Override
    public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
        ApplicationUser applicationUser = userRepository.findByUsername(username);
        if (applicationUser == null) throw new UsernameNotFoundException(username);

        return applicationUser;
    }
}

ApplicationUser.java(模型)

@Entity
@Table(name = "users")
public class ApplicationUser implements UserDetails {

    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private long id;

    @Column(unique = true, nullable = false)
    private String username;

    @Column(unique = true, nullable = false)
    private String email;

    @Column(nullable = false)
    private String password;

    public long getId() {
        return id;
    }

    public void setId(long id) {
        this.id = id;
    }

    public String getUsername() {
        return username;
    }

    public void setUsername(String username) {
        this.username = username;
    }

    public String getEmail() {
        return email;
    }

    public void setEmail(String email) {
        this.email = email;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }

    @Override
    public boolean isAccountNonExpired() {
        return false;
    }

    @Override
    public boolean isAccountNonLocked() {
        return false;
    }

    @Override
    public boolean isCredentialsNonExpired() {
        return false;
    }

    @Override
    public boolean isEnabled() {
        return false;
    }

    @Override
    public Collection<? extends GrantedAuthority> getAuthorities() {
        return null;
    }
}

JWTAuthenticationFilter

public class JWTAuthenticationFilter extends AbstractAuthenticationProcessingFilter {
    private AuthenticationManager authenticationManager;

    public JWTAuthenticationFilter(AuthenticationManager authenticationManager) {
        super(new AntPathRequestMatcher(LOGIN_URL));

        this.authenticationManager = authenticationManager;
    }

    @Override
    public Authentication attemptAuthentication(HttpServletRequest req,
                                                HttpServletResponse res) throws AuthenticationException {
        try {
            ApplicationUser creds = new ObjectMapper()
                    .readValue(req.getInputStream(), ApplicationUser.class);

            return authenticationManager.authenticate(
                    new UsernamePasswordAuthenticationToken(
                            creds.getUsername(),
                            creds.getPassword(),
                            new ArrayList<>())
            );
        } catch (IOException e) {
            throw new RuntimeException(e);
        }
    }

    @Override
    protected void successfulAuthentication(HttpServletRequest req,
                                            HttpServletResponse res,
                                            FilterChain chain,
                                            Authentication auth) throws IOException, ServletException {

        String token = Jwts.builder()
                .setSubject(((ApplicationUser) auth.getPrincipal()).getUsername())
                .setExpiration(new Date(System.currentTimeMillis() + EXPIRATION_TIME))
                .signWith(SignatureAlgorithm.HS512, SECRET.getBytes())
                .compact();

        res.addHeader(HEADER_STRING, TOKEN_PREFIX + token);
    }
}

JWTAuthorizationFilter

public class JWTAuthorizationFilter extends BasicAuthenticationFilter {

    public JWTAuthorizationFilter(AuthenticationManager authManager) {
        super(authManager);
    }

    @Override
    protected void doFilterInternal(HttpServletRequest req,
                                    HttpServletResponse res,
                                    FilterChain chain) throws IOException, ServletException {
        String header = req.getHeader(HEADER_STRING);

        if (header == null || !header.startsWith(TOKEN_PREFIX)) {
            chain.doFilter(req, res);
            return;
        }

        UsernamePasswordAuthenticationToken authentication = getAuthentication(req);

        SecurityContextHolder.getContext().setAuthentication(authentication);
        chain.doFilter(req, res);
    }

    private UsernamePasswordAuthenticationToken getAuthentication(HttpServletRequest request) {
        String token = request.getHeader(HEADER_STRING);
        if (token != null) {
            // parse the token.
            String user;
            try {
                user = Jwts.parser()
                        .setSigningKey(SECRET.getBytes())
                        .parseClaimsJws(token.replace(TOKEN_PREFIX, ""))
                        .getBody()
                        .getSubject();
            } catch (SignatureException e) {
                return null;
            }

            if (user != null) return new UsernamePasswordAuthenticationToken(user, null, new ArrayList<>());

            return null;
        }
        return null;
    }
}

4 个答案:

答案 0 :(得分:1)

在您的情况下,@AuthenticationPrincipal将返回带有用户名的字符串, 您可以通过在控制器中调用存储库并通过用户名获取用户或将存储库声明为@Bean来获取用户,然后执行以下操作:

public class JWTAuthorizationFilter extends BasicAuthenticationFilter {

//Get the repository
private UserRepository userRepository;

public JWTAuthorizationFilter(AuthenticationManager authManager) {
    super(authManager);
}

@Override
protected void doFilterInternal(HttpServletRequest req,
                                HttpServletResponse res,
                                FilterChain chain) throws IOException, ServletException {
    String header = req.getHeader(HEADER_STRING);

    if (header == null || !header.startsWith(TOKEN_PREFIX)) {
        chain.doFilter(req, res);
        return;
    }

    UsernamePasswordAuthenticationToken authentication = getAuthentication(req);

    SecurityContextHolder.getContext().setAuthentication(authentication);
    chain.doFilter(req, res);
}

private UsernamePasswordAuthenticationToken getAuthentication(HttpServletRequest request) {
    String token = request.getHeader(HEADER_STRING);
    if (token != null) {
        // parse the token.
        String user;
        try {
            user = Jwts.parser()
                    .setSigningKey(SECRET.getBytes())
                    .parseClaimsJws(token.replace(TOKEN_PREFIX, ""))
                    .getBody()
                    .getSubject();
        } catch (SignatureException e) {
            return null;
        }

        //Get your user
        UserEntity userEntity = this.userRepository.findByUsername(user);

        if (user != null) {
             //Seting in your AuthenticationPrincipal the user
             return new UsernamePasswordAuthenticationToken(userEntity, null, new ArrayList<>());
        }

        return null;
    }
    return null;
}

}

答案 1 :(得分:0)

检查您是否使用了合适的注释,因为其中一个已被弃用。

Documentation - deprecated!

Documentation - fine!

此外,请注意将用户名(String)解析为参数,而不是用户类型:

  

用于将Authentication.getPrincipal()解析为方法参数的注释。

Check this topic as well!它可以提供帮助。

我不知道这是不是很好的做法(我在Spring中不被认为是'pro'),但在我的个人项目中,我从控制器参数中传递的HttpServletRequest对象获取令牌。然后我使用JwtTokenUtil类,它有getUserFormToken(String token);方法来解析用户/用户名。它看起来像这样:

控制器

@Autowired
TestService testService;

@Autowired
UserService userService;

@Autowired
private JwtTokenUtil jwtTokenUtil;

@RequestMapping(value="/test", method = RequestMethod.GET, produces = "application/json")
@ResponseBody
public List<Test> getTestsListByUserId(HttpServletRequest req){
    String token = req.getHeader(HEADER_STRING).replace(TOKEN_PREFIX,"");
    return testService.findByUserId(userService.findByUsername(jwtTokenUtil.getUsernameFromToken(token)));
}

JwtTokenUtil

@Component
public class JwtTokenUtil implements Serializable {

public String getUsernameFromToken(String token) {
    return getClaimFromToken(token, Claims::getSubject);
}

public Date getExpirationDateFromToken(String token) {
    return getClaimFromToken(token, Claims::getExpiration);
}

public <T> T getClaimFromToken(String token, Function<Claims, T> claimsResolver) {
    final Claims claims = getAllClaimsFromToken(token);
    return claimsResolver.apply(claims);
}

private Claims getAllClaimsFromToken(String token) {
    return Jwts.parser()
            .setSigningKey(SIGNING_KEY)
            .parseClaimsJws(token)
            .getBody();
}

private Boolean isTokenExpired(String token) {
    final Date expiration = getExpirationDateFromToken(token);
    return expiration.before(new Date());
}

public String generateToken(User user) {
    return doGenerateToken(user.getUsername());
}

private String doGenerateToken(String subject) {

    Claims claims = Jwts.claims().setSubject(subject);
    claims.put("scopes", Arrays.asList(new SimpleGrantedAuthority("ROLE_ADMIN")));

    return Jwts.builder()
            .setClaims(claims)
            .setIssuer("issuer")
            .setIssuedAt(new Date(System.currentTimeMillis()))
            .setExpiration(new Date(System.currentTimeMillis() + ACCESS_TOKEN_VALIDITY_SECONDS*1000))
            .signWith(SignatureAlgorithm.HS256, SIGNING_KEY)
            .compact();
}

public Boolean validateToken(String token, UserDetails userDetails) {
    final String username = getUsernameFromToken(token);
    return (
           username.equals(userDetails.getUsername())
                   && !isTokenExpired(token));
    }

}

但是我通常会根据你的不同实现不同的过滤器。如果您有兴趣 - 我使用了this教程和实现。

答案 2 :(得分:0)

要检索自定义模型,我会做下一件事:

从数据库中获取模型并将其设置为Principal。

 private UsernamePasswordAuthenticationToken getAuthentication(HttpServletRequest request) {
        String token = request.getHeader(HEADER_STRING);
        if (token != null) {
            // parse the token.
            String user;
            try {
                user = Jwts.parser()
                        .setSigningKey(SECRET.getBytes())
                        .parseClaimsJws(token.replace(TOKEN_PREFIX, ""))
                        .getBody()
                        .getSubject();
            } catch (SignatureException e) {
                return null;
            }

            // Get user model
            ApplicationUser userModel = userRepository.findByUsername(user);

            // Set it
            if (user != null && userModel != null) return new UsernamePasswordAuthenticationToken(userModel, null, new ArrayList<>());

            return null;
        }
        return null;
    }

然后在控制器中使用@AuthenticationPrincipal注释进行检索。

public ApplicationUser getCurrentUser(@AuthenticationPrincipal ApplicationUser user) {
    return user;
}

答案 3 :(得分:0)

如果这仍然是现实的,我刚刚回答了类似的问题here

要点是从标头中提取authorization token

    HttpServletRequest request = ((ServletRequestAttributes) RequestContextHolder.currentRequestAttributes()).getRequest();
    String token = request.getHeader("Authorization").split(" ")[1];

之后,您可以对其进行解码并获得所需的部分。