Question

我正在尝试从以下API解析JSON： https://opentdb.com/api.php?amount=1

但是当我试图获取问题值时，我收到以下错误：

Exception in thread "main" java.lang.NullPointerException

我使用此代码：

public static void main(String[] args) throws IOException {
    String question;
    String sURL = "https://opentdb.com/api.php?amount=1"; //just a string

    // Connect to the URL using java's native library
    URL url = new URL(sURL);
    URLConnection request = url.openConnection();
    request.connect();

    // Convert to a JSON object to print data
    JsonParser jp = new JsonParser(); //from gson
    JsonElement root = jp.parse(new InputStreamReader((InputStream) request.getContent())); //Convert the input stream to a json element
    JsonObject rootobj = root.getAsJsonObject(); //May be an array, may be an object.
    question = rootobj.get("question").getAsString(); //grab the question

}

希望有人能告诉我自己做错了什么。

提前致谢！

Answer 1

当我看到你试图解释的JSON时，我得到：

{
    "response_code": 0,
    "results":[
        {
            "category": "Entertainment: Board Games",
            "type": "multiple",
            "difficulty": "medium",
            "question": "Who is the main character in the VHS tape included in the board game Nightmare?",
            "correct_answer": "The Gatekeeper",
            "incorrect_answers":["The Kryptkeeper","The Monster","The Nightmare"]
        }
    ]
}

此JSON不包含根成员"question"。这使rootobj.get("question")返回null，因此在其上调用getAsString会抛出NullPointerException。

因此，您必须遍历层次结构而不是rootobj.get("question")："results" - ＆gt;第一个阵列成员 - ＆gt; "question"：

rootobj.getAsJsonArray("result").getAsJsonObject(0).get("question")

Answer 2

JSON没有直接的问题＆＃34;领域。请致电question = rootobj.get("result").get(0).get("question").getAsString();

Answer 3

试试这个

question = rootobj.getAsJsonArray（“results”）。get（0）.getAsJsonObject（）。get（“question”）。getAsString（）;

Java从URL NullPointerException解析JSON

3 个答案: