Python Selenium在抓取时跳过元素

Question

index += 1导致脚本每次都跳过一个元素。因此它将打印出名称，汽车，apt_time，联系人，注释，然后不会转到下一个元素，它会跳过它并在其后打印一个，但如果我将索引设置为0，它只会重复名称，汽车，apt_time，联系，注意每个元素的第一个元素。

while 31 > today_date > 1:
    # Find calender
    div = browser.find_element_by_id('ledgerdateslider-1247-innerCt')
    # hit calender
    div.find_element_by_xpath('//*[@id="component-1250"]/div/table/tbody/tr/td[1]').click()
    # hit calender date
    browser.implicitly_wait(2)
    browser.find_element_by_link_text(str(today_date)).click()
    time.sleep(2)
    try:
        index = 0
        while True:
            header = browser.find_elements_by_class_name('x-ledgerdataview-header')
            try:
                time.sleep(2)
                header[index].click()
                while True:
                    name = browser.find_elements_by_class_name('x-lightcard-customer-name')
                    car = browser.find_elements_by_class_name('x-lightcard-vehicle-inf')
                    apt_time = browser.find_elements_by_class_name('x-lightcard-header-right')
                    contact = browser.find_elements_by_class_name('x-lightcard-contact')
                    note = browser.find_elements_by_class_name('x-lightcard-services')
                    try:
                        # print and write to file name/car/apt_time/contact/note
                        print(name[index].text)
                        f.write("\n" + 'Name: ' + name[index].text + "\n")
                        print(car[index].text)
                        f.write('Car: ' + car[index].text + "\n")
                        print(apt_time[index].text)
                        f.write('Time: ' + apt_time[index].text + "\n")
                        print(contact[index].text)
                        f.write('Contact: ' + contact[index].text + "\n")
                        print(note[index].text)
                        f.write('Service Notes:' + note[index].text + "\n")
                        print(today_date)
                        f.write('Date:' + str(today_date) + "\n")
                        time.sleep(3)
                        index += 1
                        break
                    except IndexError:
                        break