我正在尝试反序列化以下XML(摘录):
<NSArray>
<Song id="23507" type="Song">
<title>Waking The Demon</title>
<artist id="17" type="Artist">
<nameWithoutThePrefix>Bullet For My Valentine</nameWithoutThePrefix>
<useThePrefix>false</useThePrefix>
<name>Bullet For My Valentine</name>
</artist>
</Song>
<Song id="3663" type="Song">
<title>Hand Of Blood</title>
<artist id="17" type="Artist"/>
</Song>
<Song id="59226" type="Song">
<title>Your Betrayal</title>
<artist id="17" type="Artist"/>
</Song>
</NSArray>
使用以下类:
[GeneratedCode("xsd", "4.0.30319.1")]
[DebuggerStepThrough]
[XmlType(AnonymousType = true)]
[XmlRoot(ElementName = "NSArray", Namespace = "", IsNullable = false)]
public class SearchResult
{
[XmlElement("Song", Form = XmlSchemaForm.Unqualified)]
public Song[] Items { get; set; }
}
[GeneratedCode("xsd", "4.0.30319.1")]
[DebuggerStepThrough]
[XmlType(AnonymousType = true)]
[XmlRoot(Namespace = "", IsNullable = false)]
public class Song
{
[XmlElement(Form = XmlSchemaForm.Unqualified)]
public string Title { get; set; }
[XmlElement("artist", Form = XmlSchemaForm.Unqualified)]
public Artist Artist { get; set; }
[XmlAttribute]
public string Type { get; set; }
[XmlAttribute]
public string Id { get; set; }
}
[GeneratedCode("xsd", "4.0.30319.1")]
[DebuggerStepThrough]
[XmlType(AnonymousType = true)]
public class Artist
{
[XmlElement(Form = XmlSchemaForm.Unqualified)]
public string NameWithoutThePrefix { get; set; }
[XmlElement(Form = XmlSchemaForm.Unqualified)]
public string UseThePrefix { get; set; }
[XmlElement(Form = XmlSchemaForm.Unqualified)]
public string Name { get; set; }
[XmlAttribute]
public string Type { get; set; }
[XmlAttribute]
public string Id { get; set; }
}
和以下代码:
var request = WebRequest.Create(string.Format("http://myurl.com");
request.BeginGetResponse(GetEventResponseCallback, request);
private void GetEventResponseCallback(IAsyncResult result)
{
var request = (HttpWebRequest)result.AsyncState;
var response = request.EndGetResponse(result);
if (response.GetResponseStream() == null) return;
using (var stream = response.GetResponseStream())
{
_xmlReader = XmlReader.Create(stream);
var songs = _xmlSerializer.Deserialize(_xmlReader) as SearchResult;
}
}
但是,在var songs = _xmlSerializer.Deserialize(_xmlReader) as SearchResult;
上,反序列化成功执行,但songs变量不包含任何数据。如果我使用调试器进行检查,则会为数组中的所有值返回Could not evaluate expression
。
任何提示?感谢。
答案 0 :(得分:4)
您的SearchResult
课程需要一些修复。你真的很接近,代码只缺少一些元素名称和可序列化的属性。
这是一个有效的课程:
[GeneratedCode("xsd", "4.0.30319.1")]
[DebuggerStepThrough]
[XmlType(AnonymousType = true)]
[XmlRoot(ElementName = "NSArray", Namespace = "", IsNullable = false)]
[Serializable]
public class SearchResult
{
[XmlElement("Song", Form = XmlSchemaForm.Unqualified)]
public Song[] Items { get; set; }
}
[GeneratedCode("xsd", "4.0.30319.1")]
[DebuggerStepThrough]
[XmlType(AnonymousType = true)]
[XmlRoot(ElementName="Song", Namespace = "", IsNullable = false)]
[Serializable]
public class Song
{
[XmlElement("title", Form = XmlSchemaForm.Unqualified)]
public string Title { get; set; }
[XmlElement("artist", Form = XmlSchemaForm.Unqualified)]
public Artist Artist { get; set; }
[XmlAttribute("type")]
public string Type { get; set; }
[XmlAttribute("id")]
public string Id { get; set; }
}
[GeneratedCode("xsd", "4.0.30319.1")]
[DebuggerStepThrough]
[XmlType(AnonymousType = true)]
[Serializable]
public class Artist
{
[XmlElement("nameWithoutThePrefix", Form = XmlSchemaForm.Unqualified)]
public string NameWithoutThePrefix { get; set; }
[XmlElement("useThePrefix", Form = XmlSchemaForm.Unqualified)]
public string UseThePrefix { get; set; }
[XmlElement("name", Form = XmlSchemaForm.Unqualified)]
public string Name { get; set; }
[XmlAttribute("type")]
public string Type { get; set; }
[XmlAttribute("id")]
public string Id { get; set; }
}
答案 1 :(得分:0)
我有一个类,我正在序列化和反序列化。与你正在使用的属性相比......你有很多我没有的(在课堂上),但你缺少的是[Serializable]
我的样子如下:[Serializable]
public class Settings
{
[XmlElement]
public int Version { get; set; }
[XmlElement]
public string Name { get; set; }
// more settings
}
首先从像这样简单的东西开始,然后运行,然后一次添加一个新标签,你会很快发现哪一个导致它破坏。
由于您在反序列化时遇到问题,因此这是我正在使用的代码。在另一节课中,我有:
public string FilePath { get; set; }
public Settings LoadSettings()
{
XmlSerializer serializer = new XmlSerializer(typeof(Settings));
Settings settings = null;
using(TextReader reader = new StreamReader(this.FilePath))
{
settings = (Settings)serializer.Deserialize(reader);
}
return settings;
}