我使用套接字和线程在python上创建了一个文件服务器。该程序应该允许客户端从服务器上传和下载文件。
当只有一个线程正在运行时,程序运行正常,但是当两个线程都在运行时,服务器在尝试上传文件时会出错,而在尝试下载程序时,只需在客户端进入&#39后停止执行任何操作; Y'发起下载。
以下是客户端的代码:
import socket
import os
def DownloadFile(s, host, port):
s.connect((host, port))
s.send(str.encode('DNLD'))
filename = input('Filename? ->')
if filename != 'q':
s.send(str.encode(filename))
data = s.recv(2048).decode('UTF-8')
if data[:6] == 'EXISTS':
filesize = data[6:]
message = input('File Exists, ' + str(filesize) + ' Bytes. Download? (Y/N) ->')
if message == 'Y' or message == 'y':
s.send(str.encode('OK'))
f = open('copy of '+filename, 'wb')
data = s.recv(2048)
totalRecv = len(data)
f.write(data)
while totalRecv < int(filesize):
data = s.recv(2048)
totalRecv += len(data)
f.write(data)
print('{}'.format(round((totalRecv/float(filesize))*100),2)+'% Complete')
print('Download Complete!')
s.close()
else:
print('File does not exist')
s.close()
Main()
def UploadFile(s, host, port):
s.connect((host, port))
s.send(str.encode('UPLD'))
filename = input('Filename? ->')
if os.path.isfile(filename):
filesize = os.path.getsize(filename)
filesize = str(filesize)
s.send(str.encode('EXISTS ' + filename))
s.send(str.encode(filesize))
ready = input('Ready to upload. Proceed? (Y/N) ->')
if ready == 'Y' or ready == 'y':
s.send(str.encode('OK'))
with open(filename, 'rb') as f:
bytesToSend = f.read(2048)
s.send(bytesToSend)
while bytesToSend != '':
bytesToSend = f.read(2048)
s.send(bytesToSend)
s.close()
else:
print('File does not exist.')
s.close()
Main()
def Main():
host = '127.0.0.1'
port = 10000
s = socket.socket()
while True:
choice = int(input('Please enter your choice:\n\n1. Upload a file to the server.\n2. Download a file from the server\n3. Quit.\n\n->'))
if choice == 1:
UploadFile(s, host, port)
break
elif choice == 2:
DownloadFile(s, host, port)
break
elif choice == 3:
s.close()
break
else:
print('Please enter a valid choice.')
if __name__ == '__main__':
Main()
这是服务器的代码:
import socket
import threading
import os
def SendFile(name, s):
check = s.recv(2048).decode('UTF-8')
if check == 'DNLD':
filename = s.recv(2048)
if os.path.isfile(filename):
send = os.path.getsize(filename)
send = str(send)
s.send(str.encode('EXISTS ' + send))
userResponse = s.recv(2048)
userResponse = userResponse.decode('UTF-8')
if userResponse[:2] == 'OK':
with open(filename, 'rb') as f:
bytesToSend = f.read(2048)
s.send(bytesToSend)
while bytesToSend != '':
bytesToSend = f.read(2048)
s.send(bytesToSend)
else:
s.send(str.encode('ERR'))
s.close()
def ReceiveFile(name, s):
check = s.recv(2048).decode('UTF-8')
if check == 'UPLD':
data = s.recv(2048).decode('UTF-8')
if data[:6] == 'EXISTS':
filename = data[6:]
data = s.recv(2048).decode('UTF-8')
filesize = data
userResponse = s.recv(2048)
userResponse = userResponse.decode('UTF-8')
if userResponse[:2] == 'OK':
f = open('copy of '+filename, 'wb')
data = s.recv(2048)
totalRecv = len(data)
f.write(data)
while totalRecv < int(filesize):
data = s.recv(2048)
totalRecv += len(data)
f.write(data)
print('Download Complete!')
def Main():
host = '127.0.0.1'
port = 10000
s = socket.socket()
s.bind((host, port))
s.listen(5)
print('Server Started')
while True:
c, addr = s.accept()
print('Client Connected: ' + str(addr))
Send = threading.Thread(target=SendFile, args=('sendThread', c))
Send.start()
Receive = threading.Thread(target=ReceiveFile, args=('retrThread', c))
Receive.start()
s.close()
if __name__ == '__main__':
Main()
如果我要注释掉Send.start()或Receive.start(),那么任何未被注释掉的线程都可以正常工作。
以下是在尝试上载运行两个线程的文件时服务器中给出的错误:
Exception in thread Thread-2:
Traceback (most recent call last):
File "C:\Python34\lib\threading.py", line 920, in _bootstrap_inner
self.run()
File "C:\Python34\lib\threading.py", line 868, in run
self._target(*self._args, **self._kwargs)
File "(file location)", line 28, in ReceiveFile
check = s.recv(2048).decode('UTF-8')
OSError: [WinError 10038] An operation was attempted on something that is not a socket
以下是两个线程运行时尝试下载文件时客户端的输出:
Please enter your choice:
1. Upload a file to the server.
2. Download a file from the server
3. Quit.
->2
Filename? ->cat.jpg
File Exists, 10634 Bytes. Download? (Y/N) ->Y
进入Y后没有其他事情发生。
如果有人知道出了什么问题,我真的很感激一些帮助。
答案 0 :(得分:0)
这不是io和线程的工作方式。这里有2个线程从相同的输入数据竞争。一个人将获得第一个数据包是否为它,并且很可能以下数据包中的一个将被另一个数据包吃掉=&gt;第一个永远不会看到它!
您可以将会话的处理委派给一个线程,但是一旦它确定了请求就会调用一个将调用发送或接收功能的线程。
这不是全部。 TCP是流协议。数据包可以通过连接(发送方,接收方和任何网关)的任何部分进行拆分或重新组装。因此,您应该使用分隔符告诉对等方名称或命令是否完整。并且好的做法建议在发送二进制数据时传递大小,这里同样要让对等方知道数据何时完成。
祝你旅途中的好运是套接字世界; - )