Question

是否可以按表中的字符选择最短和最长的字符串？

我有一个类型为CITY的{{1}}列，我希望按字母顺序选择最短和最长的城市名称。

我这样做了

VARCHAR(20)

按字母顺序排序时，让CITY名称列为ABC，DEF，PQRS和WXY，各自的长度分别为3,3,4和3.最长的城市显然是PQRS，但有最短的选项 - 命名的城市;我必须选择ABC，因为它首先按字母顺序排列。

我的查询结果是所有三个城市的长度都为3。

SELECT CITY,LENGTH(CITY) FROM STATION WHERE LENGTH(CITY) IN ( SELECT MAX(LENGTH(CITY)) FROM STATION UNION SELECT MIN(LENGTH(CITY)) FROM STATION ) ORDER BY CITY ASC;

SELECT的结果必须是

ABC 3 DEF 3 PQRS 4 WXY 3

Answer 1

您可以使用UNION运算符

(SELECT CITY, MAX(LENGTH(CITY)) FROM STATION)
UNION
(SELECT CITY, MIN(LENGTH(CITY)) FROM STATION)
ORDER BY CITY ASC LIMIT 1;

更多示例https://dev.mysql.com/doc/refman/8.0/en/union.html

Answer 2

尝试这些查询。

最长城市名称::

select CITY from STATION where char_length(CITY) = (select max(char_length(CITY)) from STATION)

最短城市名称::

select CITY from STATION where char_length(CITY) = (select min(char_length(CITY)) from STATION)

Answer 3

如果我理解正确的话，我认为你需要union子查询：

select s.*
from station s
where length(city) in (select max(length(city)) 
                       from station 
                       union 
                       select min(length(city)) 
                       from station)
order by length(city);

Answer 4

无论如何我得到了答案

SELECT CITY,LENGTH(CITY)
FROM STATION
WHERE LENGTH(CITY) IN (
  SELECT MAX(LENGTH(CITY))
  FROM STATION
  UNION
  SELECT MIN(LENGTH(CITY))
  FROM STATION
)
ORDER BY LENGTH(CITY) DESC,CITY ASC LIMIT 2;

Answer 5

我知道您已经选择了答案，但这是一个简短的答案，可能会有所帮助。这是使用Microsoft MySQL Server，但也可以使用调用LIMIT而不是TOP轻松转换为任何其他类型。

最长

SELECT TOP 1 CITY, LEN(CITY)
FROM STATION 
ORDER BY LEN(CITY) ASC, CITY ASC;

最短长度

SELECT TOP 1 CITY, LEN(CITY)
FROM STATION 
ORDER BY LEN(CITY) DESC, CITY ASC;

Answer 6

我发现这很简单：

`选择城市，从中选择城市长度（从按车站长度排序的城市中选择城市（城市ASC，城市ASC） WROWE ROWNUM = 1;

选择城市，从中选择城市长度（从按车站长度排序的城市中选择城市（城市）DESC，城市ASC） WROWE ROWNUM = 1;`

Answer 7

我已经尝试过了，找到了MySQL数据库查询的解决方案，

(SELECT CITY, LENGTH(CITY)
FROM STATION 
ORDER BY LENGTH(CITY) ASC, CITY ASC LIMIT 1)
UNION
(SELECT  CITY, LENGTH(CITY)
FROM STATION 
ORDER BY LENGTH(CITY) DESC, CITY ASC LIMIT 1)

我认为使用LIMIT比行号更好。

Answer 8

请在下面的查询中找到此内容：

SELECT top 2 CITY,LEN(CITY)
FROM STATION
WHERE LEN(CITY) IN (
  SELECT MAX(LEN(CITY))
  FROM STATION
  UNION
  SELECT MIN(LEN(CITY))
  FROM STATION
)
ORDER BY LEN(CITY) DESC,CITY ASC ;

Answer 9

更清洁的方式：

SELECT CITY, LENGTH(CITY) FROM STATION ORDER BY LENGTH(CITY) ASC, CITY ASC LIMIT 1;
SELECT CITY, LENGTH(CITY) FROM STATION ORDER BY LENGTH(CITY) DESC, CITY ASC LIMIT 1;

Answer 10

SELECT CITY, LENGTH(CITY) FROM STATION ORDER BY LENGTH(CITY),CITY LIMIT 1;

SELECT CITY, LENGTH(CITY) FROM STATION ORDER BY LENGTH(CITY) DESC, CITY LIMIT 1;

上面的代码应该很容易理解并且易于理解。第一个查询显示最短的城市名称及其长度。第二个输出最长。

Answer 11

@DecimalMax

选择最短和最长的字符串

11 个答案: