Question

大家好，我有一个关于检查字符串的问题，我想通过订单检查单词中的特定字符

Ah = "a","h","i"
Oo= "o", "y","wh"


text = "whats going on my friend?"
text_splited = text.split()
for word in text_splited:
    print "Checking this :",word
    for ph in Ah:
       if ph in word:
          print ph
    for ph in Oo:
       if ph in word:
          print ph

结果如下：

Checking this : whats
a
h
wh
Checking this : going
i
o
Checking this : on
o
Checking this : my
y
Checking this : friend?
Lip  : i

例如“whats”预期结果是“wh”，“h”，“a”（按顺序）任何人都可以提供帮助，请：）

由于

Answer 1

如果您不关心Oo和Ah元素的混合。这可能有效：

Ah = "a","h","i"
Oo= "o", "y","wh"


text = "whats going on my friend?"
text_splited = text.split()
for word in text_splited:
    list1 = []
    list2 = []
    print("Checking this :",word)
    for ph in Ah:
        list1.append((word.find(ph),ph)) #to preserve the index of element

    list2.extend(list1)
    for ph in Oo:
        list2.append((word.find(ph),ph)) #to preserve the index of element
    list2.sort(key=lambda x:x[0])
    for i in list2:
          if(i[0]>=0):
            print(i[1])

我们只是按排序顺序打印找到的元素。上述代码的输出是：

Checking this : whats
wh
h
a
Checking this : going
o
i
Checking this : on
o
Checking this : my
y
Checking this : friend?
i

按顺序检查String中的特定字符

1 个答案: