Pdo预处理语句将NULL插入表字段,oop php

时间:2018-06-10 20:40:28

标签: php mysql pdo prepared-statement

我正在尝试创建一个oop登录系统并且卡在这个

Soo,这是我的插入类

include_once 'db.php';

class loginHandler extends db {

    private $login;
    private $password;
    private $email;
    private $stmt;

    public function __construct ($l,$p,$e) {

        $this->login = $l;
        $this->password = $p;
        $this->email = $e;
        $this->stmt = $this->connect()->prepare("INSERT INTO users (log,pwd,email) VALUES (?,?,?);");

    }

    public function send () {

        $this->stmt->execute([$this->login,$this->password,$this->email]);

    }

}

这就是提交按钮的位置

include 'loginHandler.php';

$log = $_POST['log'];
$pwd = $_POST['pwd'];
$em = $_POST['email'];

$buffer = new loginHandler ($log,$pwd,$em);
$buffer->send();

因此,当它运行时,表字段填充“NULL”而不是输入中的实际数据

1 个答案:

答案 0 :(得分:0)

您需要在_POST

之前添加$ sign
$log = $_POST['log'];
$pwd = $_POST['pwd'];
$em = $_POST['email'];