Question

我有以下查询：

$clinics =  \DB::select('SELECT * FROM
(SELECT *,
 (100 * acos(cos(radians(' . $lat . ')) * cos(radians(lat)) *
 cos(radians(lng) - radians(' . $lng . ')) +
 sin(radians(' . $lat . ')) * sin(radians(lat))))
 AS distance
 FROM clinics) AS distances
 WHERE distance < 100
 ORDER BY distance')
 ->join('countries', 'clinics.country_id', '=', 'countries.id');

当我运行它时，我收到以下错误：

Symfony \ Component \ Debug \ Exception \ FatalThrowableError (E_ERROR)
Call to a member function join() on array

是否可以使用此查询执行 JOIN ？我尝试在select查询中添加 JOIN ，但我收到错误：

Column not found: 1054 Unknown column 'clinics.country_id' in 'on clause' (SQL: SELECT * FROM (SELECT *, (100 * acos(cos(radians(43.1557012)) * cos(radians(lat)) * cos(radians(lng) - radians(22.5856811)) + sin(radians(43.1557012)) * sin(radians(lat)))) AS distance FROM clinics) AS distances JOIN countries ON countries.id = clinics.country_id WHERE distance < 100 ORDER BY distance)

有问题的查询：

$clinics =  \DB::select('SELECT * FROM
    (SELECT *,
     (100 * acos(cos(radians(' . $lat . ')) * cos(radians(lat)) *
     cos(radians(lng) - radians(' . $lng . ')) +
     sin(radians(' . $lat . ')) * sin(radians(lat))))
     AS distance
     FROM clinics) AS distances
     JOIN countries ON countries.id = clinics.country_id
     WHERE distance < 100
     ORDER BY distance');

Answer 1

从我所看到的，子查询不是必需的，您可以将查询转换为Laravel表示法，如下所示：

$clinics = Clinic::join('countries', 'countries.id', '=', 'clinics.country_id')
    ->selectRaw('clinics.*, countries.*, (
        100 * acos(
            cos(radians(?)) *
            cos(radians(lat)) *
            cos(radians(lng) - radians(?)) +
            sin(radians(?)) * sin(radians(lat))
        )
    ) as distance', [$lat, $lng, $lat])
    ->having('distance', '<', 100)
    ->orderBy('distance')
    ->get();

您可能希望明确列出要为countries表选择的列，因为使用countries.*您将覆盖id表的clinics列。我添加了countries.*，因为我想这是你加入表后想要做的事情。

Laravel 5.6 - DB select调用数组上的成员函数join（）

1 个答案: