Question

我在点击“菜单”时尝试创建一个下拉菜单＆＃39;一句话，但它不起作用。内容已隐藏import os import sys import json import time import base64 import urllib import urllib2 def main(): if len(sys.argv) != 2: print 'Usage: python {} [api-key]'.format(sys.argv[0]) return to_check = ('inputs', 'processed', 'outputs') if any([not os.path.exists(x) for x in to_check]): print 'The script expects the following folders to exist: {}'.format(', '.join(to_check)) answer = None while answer is None or answer.lower() not in ['y', 'n']: answer = raw_input('Do you want the script to create them? [yn] ').lower() if answer == 'n': return for folder in to_check: if not os.path.exists(folder): os.makedirs(folder) print 'Using API key: {}\n'.format(sys.argv[1]) before = [] while True: files = os.listdir('inputs') added = [f for f in files if f not in before] removed = [f for f in before if f not in files] print 'Added:', added print 'Removed:', removed print 'Processing new files..' for file in added: parts = os.path.splitext(os.path.basename(file)) text_path = os.path.join('outputs', '.'.join(parts[:-1]) + '.txt') processed_path = os.path.join('processed', os.path.basename(file)) if os.path.exists(text_path): print('Output file already exists, just moving image.') os.rename(os.path.join('inputs', file), processed_path) else: process(os.path.join('inputs', file), text_path) os.rename(os.path.join('inputs', file), processed_path) print('---') before = files time.sleep(5) def process(fname, output): print('Processing {}'.format(fname)) url = 'https://vision.googleapis.com/v1/images:annotate?' + urllib.urlencode({'key': sys.argv[1] }) payload = json.dumps(get_payload([fname], 5)).encode('utf-8') request = urllib2.Request(url) request.add_header('Content-Type', 'application/json') request.add_header('Content-Length', len(payload)) try: response = json.loads(urllib2.urlopen(request, payload).read()) except urllib2.HTTPError as e: print('Wrong api key. Please check it.') print(e.read()) sys.exit(1) return text_response = response['responses'][0] text = text_response['fullTextAnnotation']['text'] with open(output, 'wb+') as file: file.write(text.encode('utf-8')) print('Done! Text written to {}'.format(output)) def get_payload(paths, max_results): requests = [] for path in paths: with open(path, 'rb') as file: content = {'content': base64.b64encode(file.read()).decode('utf-8')} requests.append({ 'image': content, 'features': [{'type': 'TEXT_DETECTION', 'maxResults': max_results}] }) return {'requests': requests} if __name__ == '__main__': main()，我使用了display:none伪类和所有内容。欢迎任何帮助。提前谢谢！

也可以在JSFiddle上检查代码：https://jsfiddle.net/pys0wLo3/

HTML：

:checked

CSS：

<div class="menu" style="text-align: center;">
  <input type="checkbox" id="toggle">    
  <label for="toggle">MENU ☰</label>
  <ul>
        <a href="#"><li>Página principal</li></a>
        <a href="#"><li>Textos</li></a>
        <ul>
              <a href="#"><li>VAVEL Brasil</li></a>
              <a href="#"><li>Doislances</li></a>
              <a href="#"><li>Outros</li></a>
        </ul>
        <a href="sobre.html"><li>Sobre mim</li></a>
         <a href="#"><li>Contato</li></a>
  </ul>

Answer 1

#toggle：checked~ul

#toggle

没有兄弟.menu

Answer 2

在您的代码中，以下细分意味着什么

#toggle:checked ~ .menu ul {}

<input checked>
<tag class="menu">
 <ul></ul> <!-- the above css will select this when you check the input -->
</tag>

我对你的小提琴做了一个小修改。请检查一下。 https://jsfiddle.net/cujslive/dy3pqcja/1/

带复选框黑客的下拉菜单不起作用

2 个答案: