Python - 我的脚本在最大请求重试后是否正确重试？

Question

所以我一直在研究一个监视URL的监视器，它检查URL的末尾是否有“/ Password” - 如果有，打印出url中没有密码，如果有的话，几秒后重试随机。

有时我发生的事情是，当我检查时，我有时会遇到Maxretries错误，导致我收到错误并杀死脚本。我想做和做的是每当出现错误时 - 再次重试，现在我想问问你们我是否做得正确或是否有比这更好的方法？

public class Test_korn
{

    public static void main(String[] args)
    {   

     double grain ,gram, kilo, ton, container, ship;    
     int i; 

     grain = 1; 
            i = 1; 


    System.out.println( i  + ". field:  " + (int) grain + " grains" );            

     while(i <= 63)  // 2^0 = 1  bis  2^63!
        {   
        grain *=  2 ; 

        if (grain/100 <= 1)  
            {
            System.out.println( (i+1)  + ". field:  " + (int) grain + " grains" );  
            }

        else if( grain/100 > 1 && grain/10_000 <= 1 )   
            {
            gram = grain/10;    
            System.out.println( (i+1) + ". field:  " + gram + " grams" );   
            }

        else if( grain/10_000 > 1 && grain/(10_000 * 1000) <= 1)  
            {
            kilo = grain/(10 * 1000);   
            System.out.println( (i+1)  + ". field:  " + kilo + " kilogram" );       
            }

        else if( grain/(10_000 * 1000) > 1  &&  grain/(10_000 * 1000 * 1000)  <= 1 )  
            {
            ton = grain/( 10 * 1000 * 1000);    
            System.out.println( (i+1)  + ". field:  " + ton + " tons" ); 
            }

        else if(   grain/(10_000 * 1000 * 1000)  > 1   &&  grain/(10_000 * 1000 * 1000 * 1000)  <= 1  )    
            {
            container = grain/(10 * 1000 * 1000 *1000);     
            System.out.println( (i+1)  + ". field:  " + container + " container" );     
            }

        else if(  grain/(10_000 * 1000 * 1000 * 1000)  > 1 )   
            {
            ship = grain/(10000 * 1000 * 1000 * 1000 * 1000);   
            System.out.println( (i+1)  + ". field:  " + ship + "container ship" );                  
            }   

        i++;    
        }       
    }
}