Question

检查标题中的年份如果找到了年份之前的字符串egtestmovie，我该怎么办？

int main()
{
    string title = "testmovie2015.mkv";
    for (int year = 2000; year <= 2018; year++)
    {
        // code
    }
}

Answer 1

string类有两个在这里很有用的功能：find和substr。

与to_string一起，您可以使用它们：

#include <iostream>
#include <string>

int main() {
    std::string title = "testmovie2015.mkv";
    int y = 2015;
    std::string year = std::to_string(y);
    std::string::size_type n = title.find(year);
    if (n != std::string::npos)
    {
        std::string a = title.substr(0, n);
        std::cout << a << std::endl;
    }

    return 0;
}

Answer 2

这很有效。

#include <string>
#include <iostream>
using namespace std;
int main()   {  
char title[20] = "testmovie2015.mkv";
int year=0,i=0;
for(i=0;title[i]!='\0';i++){
if(isdigit(title[i])&&isdigit(title[i+1])&&isdigit(title[i+2])&&isdigit(title[i+3]))
{   year=1;
    break; 
}
                    }
if(year)
{
 year=((title[i]-'0')*1000)+((title[i+1]-'0')*100)+((title[i+2]-'0')*10)+(title[i+3]-'0');
 if(year>=2000&&year<=2018)
 {   int k=0;
     while(k<i)
     {   
         cout<<title[k];
         k++;
     }
 }
 else
 {
     cout<<"Year found: "<<year<<", but out of given range";
 }
}
else
{
    cout<<"No year found in the string";
}

        }

在字符串中查找循环值

2 个答案: