Question

我创建了一个测试表单，只是为了尝试将来自性别表（包含：（1）Male（2）Female）的单选按钮值发送到另一个名为ajebaje的MySQL表。我现在遇到问题。下面的代码只是一个测试，我希望单选按钮提交值，但它不是。

<!DOCTYPE html>
<html>
    <head>
        <meta charset="utf-8">
        <title> ajebaje </title>
    </head>
    <body>
        <form name="form1" action= "<?php echo $_SERVER["PHP_SELF"]; ?>"  method="post"> 
             <table width="20%" border="0" cellspacing="1" cellpadding="3">
                <tr>
                    <td><h4> Student's Gender </h4></td>
                    <td>
                        <?php
                            $con=mysqli_connect("localhost", "root", "ew6wLoLOro", "result");
                            $sql=mysqli_query($con, "select gender_sl_no, gender_name from gender")                
                            while($row=mysqli_fetch_array($sql))
                            {
                                 echo '<table>
                                           <input type="radio" name="sexbd" checked="checked"/>'.$row['gender_name'].'           
                                       </table>';
                            }
                        ?>
                   </td>
               </tr>  
               <tr>
                   <td> </td>
                   <td><input type ="submit" name="submit"/> </td>
               </tr>
           </table>
       </form>
       <?php
           $con=mysqli_connect("localhost", "root", "ew6wLoLOro", "result");
           $sexbd = $_POST['sexbd'];
           if(isset($_POST['submit']))
           {    
               echo $que="Insert into ajebaje VALUES(default,'$sexbd' )";
               echo " ";
               echo "Your Data Inserted";
               $result = mysqli_query($con,$que);
           }
       ?>
   </body>
</html>

Answer 1

默认情况下，它应该在表单中发送public ActionResult VendorOrderListPartial() { var model = VendorManager.GetAllVendorOrders(); ViewBag.paging = GlobalSettingsInfo.GridPageSize; var grid = this.gridMvcHelper.GetAjaxGrid(model.AsQueryable().OrderByDescending(x => x.OrderId)); return View("VendorOrderListPartial", grid); } @Html.Grid(Model).Named("VendorOrderListPartial").Columns(columns => { columns.Add(c => c.OrderNo).Titled("Ord#").Filterable(true); columns.Add(c => c.OrderDate).Format("{0:dd/MM/yyyy}").Titled("Order Date").Filterable(true); columns.Add(c => c.ProdStatus).Titled("Prod.Status").Filterable(true); columns.Add(c => c.OrderAmount).Titled("Total Amount").Filterable(true); columns.Add().Titled("View").Filterable(false).RenderValueAs(o => Html.ActionLink("View", "VendorOrderDetailView", "WebVendor", new { id = o.OrderId }, null)).Encoded(false).Sanitized(false); }).WithPaging(@ViewBag.paging).Sortable(true)。

要从表单发送值，需要在input标记中定义value属性。像这样：

sexbd: on

，呈现的表单如下所示：

echo '<table>
          <input type="radio" name="sexbd" checked="checked" value='.$row['gender_name'].'/>'.$row['gender_name'].'
      </table>';

现在，提交的值将为<!DOCTYPE html> <html> <head> <meta charset="utf-8"> <title> ajebaje </title> </head> <body> <form name="form1" action= "/test" method="post"> <table width="20%" border="0" cellspacing="1" cellpadding="3"> <tr> <td><h4> Student's Gender </h4></td> <td> <table> <input type="radio" name="sexbd" checked="checked" value="Male"/> Male </table> <table> <input type="radio" name="sexbd" checked="checked" value="Female"/> Female </table> </td> </tr> <tr> <td> </td> <td><input type ="submit" name="submit"/> </td> </tr> </table> </form> </body> </html>或sexbd: Male

如何插入复选按钮的选中值，这是来自php

1 个答案: