Question

C ++ newbie here。

我有3个字符串

const char section1[] = {0x12, 0x34, 0x56, 0x78};
std::wstring section2 = L"section2";
const char section3[] = {0x23, 0x45, 0x67, 0x89};

我需要将它们加在一起，结果看起来像

{0x12,0x34,0x56,0x78,0x73,0x00,0x65,0x00,0x63,0x00,0x74,0x00,0x69,0x00,0x6f 0x6e，0x00,0x32,0x00,0x23,0x45,0x67,0x89} < / p>

因此，两个带有Unicode部分的ASCII位夹在中间。加入它们的最佳方式是什么，以及要输出到文件的最佳数据类型是什么？

Answer 1

std::vector<unsigned char> Buffer;

for (size_t i = 0; i < sizeof(section1); ++i)
  Buffer.push_back((unsigned char) section1[i]);

for (size_t i = 0; i < section2.size(); ++i) {
  unsigned short u = (unsigned short) section2[i];
  Buffer.push_back((unsigned char) (u >> 8));
  Buffer.push_back((unsigned char) (u & 0xFF));
}

for (size_t i = 0; i < sizeof(section3); ++i)
  Buffer.push_back((unsigned char) section31[i]);

您还可以将memcpy用于第1节和第3节，如果您也对第2节的字节顺序进行了假设。上面的循环应该易于阅读和理解。

完成后，您只需从＆amp; Buffer [0]

开始写入Buffer.size（）字节

在c ++中使用wchar_t字符串连接和存储char字符串的最佳方法

1 个答案: