'on子句'中的未知列（列别名可能导致错误）

Question

我有查询，曾经在MariaDB 10.2.15上工作。升级到MariaDB 10.3.7后，此查询不再起作用，我不知道原因。

查询看起来像这样：

WITH
 table_1 AS (SELECT id AS 'first_id' FROM some_table),
 table_2 AS (select id AS 'second_id' FROM another_table)
SELECT *
FROM table_1 
LEFT OUTER JOIN table_2 ON table_1.first_id = table_2.second_id
UNION
SELECT *
FROM table_1
RIGHT OUTER JOIN table_2 ON table_1.first_id = table_2.second_id

如果我尝试运行此查询，则会收到错误Unknown column 'table_2.second_id' in 'on clause'。现在它变得奇怪了，因为当我修改查询（从连接列中删除别名）到这样的东西（见下文）时，一切正常。

WITH
 table_1 AS (SELECT id FROM some_table),
 table_2 AS (select id FROM another_table)
SELECT *
FROM table_1 
LEFT OUTER JOIN table_2 ON table_1.id = table_2.id
UNION
SELECT *
FROM table_1
RIGHT OUTER JOIN table_2 ON table_1.id = table_2.id

编辑1： 我试图将查询更改为此，但仍然无效。

WITH
 table_1 AS (SELECT id AS `first_id` FROM some_table),
 table_2 AS (select id AS `second_id` FROM another_table)
SELECT *
FROM table_1 
LEFT OUTER JOIN table_2 ON table_1.first_id = table_2.second_id
UNION
SELECT *
FROM table_1
RIGHT OUTER JOIN table_2 ON table_1.first_id = table_2.second_id

编辑2： 我很确定，first_id列存在，因为当我运行查询时，我可以在检索到的结果中看到所需的列。我想在LEFT OUTER JOIN过程中我的别名列会丢失。

WITH
 table_1 AS (SELECT id AS `first_id` FROM some_table),
 table_2 AS (select id AS `second_id` FROM another_table)
SELECT *
FROM table_1