我的情况是Subject正在返回错误，但订阅Observable的{{1}}的错误方法正在执行，即使订阅Subject {1}}不会失败并返回错误。像这样：
Observable在此代码中，正在执行this.createPayment$ = this.wizard$.pipe(
switchMap((wizard) => willReturnAnErrorObservable()),
share()
);
this. handleSuccessSubscription = this.createPayment$.pipe(
filter((someEvent: SomeEvent) => event.succeeded),
switchMap((someEvent: SomeEvent) =>
// this is never called because the filter above does not pass
doesNotFailObservable()
)
).subscribe((confirmedPayment: PaymentDeviceEvent) => {
// not important
},
(error) => {
// this error block is still being called, even though the this.
// handleSuccessSubscription switchMap is not executed, because the
// this.handleSuccessSubscription$ above returns an error
});
的错误方法，即使createPaymentSuccessfulSubscription返回正常，这是因为＆＃39;外部＆＃39; switchMap正在抛出错误。
有没有办法阻止订阅者也收到错误？它并不重要，因为我可以对返回的Subject进行过滤，以确定是否需要在此处理;但它有点臭，我希望这个错误块不会被执行。
答案 0 :(得分：0)
在传递给最终消费者
之前，您应该捕获错误并处理它们import { of } from 'rxjs';
import { catchError, switchMap, share } from 'rxjs/operators';
this.createPayment$ = this.wizard$.pipe(
switchMap((wizard) => willReturnAnErrorObservable()),
catchError((error) => of(console.log('log error', error))),
share(),
);