Question

所以，这是任务。无法解决，请帮忙。

check_guess（）需要2个字符串参数：letter和guess（都期望单个字母字符） - 如果猜测不是字母字符打印无效并返回False - 测试并打印，如果猜测是＆＃34;高＆＃34;或＆＃34;低＆＃34;并返回False - 测试并打印，如果猜测是＆＃34;正确＆＃34;并返回True

Letter Guess

创建letter_guess（）函数，为用户提供3个猜测

为答案信取一个字母字符参数获取用户输入的字母猜测用回答和猜测来调用check_guess（）结束letter_guess如果 check_guess（）等于True，返回True 或者在3次尝试失败后，返回False

首先，我无法解决3次尝试。第二个问题是，当我输入前的数字时，我无法犯错误。

letter = "J"
tries = 3

guess = input ("Enter your guess ")


def check_guess (guess, letter):


if letter == guess.upper():
    print ("correct")
    True
    return 

elif letter < guess.upper():
    print ("You are wrong, but go closer to A")
    False
    return 
elif letter > guess.upper():
    print ("You are wrong, but go closer to Z")
    False
    return 

def letter_guess (guess, letter, tries):
if check_guess (guess, letter) == True:
    pass
elif check_guess (guess, letter) == False:
    tries - 1
    return

if tries == 0:
print ("GAME OVER!")
else:
check_guess (guess, letter)

Answer 1

您没有使用letter_guess功能，并且您没有从None功能返回结果（check_guess除外）。
试试这个：

letter = "J"
tries = 3

def check_guess (guess, letter):
    if not guess.isalpha():
        print("Invalid")
        return False
    if letter == guess.upper():
        return True
    elif letter < guess.upper():
        print ("Your guess is High")
        return False
    else:
        print ("Your guess is Low")
        return False

def letter_guess():
    for i in range(tries):
        guess = input ("Enter your guess ")
        res = check_guess (guess, letter)
        if res:
            print ("Correct!")
            return True
    return False

result = letter_guess()
if result:
    print ("Congratulations")
else:
    print ("The answer was ",letter)
print ("GAME OVER!")

Answer 2

通过删除letter_guess函数并将所有游戏逻辑压缩成一个函数，可以简化代码。

然后为了解决3次尝试的问题，我做了一个循环，循环直到尝试== 0.当循环命中一个猜测错误的语句时，它减去一次尝试。

我还必须移动

guess = input ("Enter your guess ")

进入while循环，因此它会多次迭代并获得三次不同尝试的输入。

correctLetter = "J"

def check_guess (letter):

    tries = 3

    while tries > 0:

        guess = input ("Enter your guess ")

        if letter == guess.upper():                
            print ("Correct!")
            break

        elif letter < guess.upper():
            if tries > 1:
                print ("You are wrong, but go closer to A")
            tries = tries - 1    #Moves you closer to finishing the loop

        elif letter > guess.upper():
            if tries > 1:
                print ("You are wrong, but go closer to Z")  
            tries = tries - 1  #Moves you closer to finishing the loop

    if tries == 0:
        print ("GAME OVER!")

check_guess(correctLetter)

附注：要从函数返回任何值，该值需要直接遵循return语句，如下所示：

return True

我希望有所帮助！

Answer 3

这实现了相同的功能，但使用了两种不同的功能。

var credCache = new CredentialCache();
var basicCred = new NetworkCredential(htaccessUsername, htaccessPassword);
var digestCred = new NetworkCredential(username, apiKey);
credCache.Add(new Uri("http://.com/"), "Basic", basicCred);
credCache.Add(new Uri("http://.com/"), "Digest", digestCred);
var httpClient = new HttpClient(new HttpClientHandler { Credentials = credCache });

函数letter_game运行游戏，而letter_check函数返回一个布尔值，对应于猜测的字母是否与正确的字母匹配。

猜一封字母A-Z

3 个答案: